SCOTT CHRISTIAN COLLEGE (AUTONOMOUS), NAGERCOIL, TAMILNADU, INDIA
Department: …………………………………………. Programme: …………………………… Course CodeTitle : ……………………………………………………………………………..…
Question Type / Difficulty Level / Cognitive Level (Ref. Bloom’s Taxonomy)Code / Question Type / Marks
1 / Multiple Choice / 1
2 / Short Answer / 5
3 / Essay – Open type / 15
4 / Essay- Closed type / 15
5 / Problem / 15
5 marks – able to answer in 9 Minutes
15 Marks – able to answer in 27 Minutes / Code / Difficulty Level
1 / Basic
2 / Standard
3 / Challenging
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Support: +91 9443746555 / Code / Cognitive Level / Question Stems
1 / Remember / Describe, Define, How, State etc.
2 / Understand / Classify, Compare, Demonstrate, Explain etc
3 / Apply / Apply, Construct, Solve, Develop etc
4 / Analyze / Analyze, Discover, Examine, Survey etc
5 / Evaluate / Assess, Interpret, Justify, Prove, etc
6 / Create / Build, Compose, Create, Design, Predict, etc.
Unit-Section / Question
Type / Difficulty Level / Cognitive
Level / Question / Answer Hints
OR
Correct Answer for MCQ in Choice 1
1.1 / 1 / 1 / 1 / The equation 7x + 7y = 12 belongs to which type? / a) Linear
b) Quadratic
c) Transcendental
d) Polynomial
1.1 / 2 / 1 / 2 / Why is ‘Bisection method’ called as bracketing method? / Location of root is confined within an interval
1.2 / 5 / 2 / 3 / Find the root ofthe equation x4-x-10 = 0 with intial guess a = 1.5 and b = 2 / Root estimate c = (a+b)/2
Ans: 1.86
2.1 / 5 / 3 / 3 / Find a root ofthe equation 3x + sin(x) - exp(x) = 0in theinterval[0, 0.5] / Root estimate c = (a+b)/2
Ans: 0.3605
2.2 / 2 / 2 / 2 / How will you choose the initial guesses for bracketing methods? / Function values must have opposite sign inside an interval. So it has a root in that interval.
2.1 / 1 / 2 / 2 / Bracketing methods are based on the idea as the sign of the function: / a) changes near the vicinity of the root
b) is zero near the vicinity of the root
c) is positive near the vicinity of the root
d) is negative near the vicinity of the root
2.5 / 1 / 2 / 1 / Muller’s method uses the quadratic formula for its solution / a)
b)
c)
d)
2.5 / 3 / 2 / 5 / Describe the theory of finding roots of an equation using False – Position method. /
3.4 / 5 / 2 / 5 / Fit a natural cubic spline of the following data
X / 1 / 2 / 3
y / -8 / 1 / 18
Compute y(1.5) /
Ans: -6.25
4.2 / 2 / 2 / 3 / Define various difference formulae for interpolation / Forward difference
Backward difference
Central difference
5.7 / 5 / 2 / 4 / /