Physics 11 Name:

Take Home Quiz: Kinematics (1) Date:

Block:

1.  After 18.5 s, a jogger’s displacement is 250 meters. What is the average velocity of the jogger? (2 marks)

2.  How far does a plane fly in 15 seconds, while it’s velocity is changing from 145 m/s to 75 m/s at a uniform rate of acceleration? (3 marks)

3.  A sports car at a starting line of a race can move 120. metres in the first 4.90 seconds of uniform acceleration. Find the car’s acceleration. (3 marks)

4.  A skateboard rider starts from rest and accelerates at a constant 0.50 m/s2 for 8.4 seconds. What is the rider’s displacement during this time? (3 marks)

5.  A car speeds up from 50.0 m/s to 100.0 m/s in 3.00 s. How far did the car travel during this acceleration? (3 Marks)

d = vit + 0.5 at2 a = ∆v÷t

a = 50÷3 = 16.7 m/s2

d = 50 x 3 + 0.5 x 16.7 x 9

d = 225 m

6.  A cyclist passes a race checkpoint at 5.5 m/s and then accelerates at a constant rate of 0.65 m/s2. The cyclist forgot to check in at the checkpoint, and after 20 s turns around to head back. How far did the cyclist move from the checkpoint to the point of turning back? (3 marks)

7.  Police find skid marks 60 m long on a highway showing where a car made an emergency stop. Assuming that the car can accelerate at -10. m/s2 (about the maximum for dry pavement), how fast was the car going? Was the car exceeding the 80 km/h speed limit? (4 Marks)

8.  A car is traveling with a velocity of 24.4 m/s. It accelerates at a constant rate of -20 m/s2. If the acceleration lasts for 5.6 seconds, what is the final velocity of the car? (3 marks)

9.  Use the following graph to answer the questions below:

a) What is the velocity of section A in m/s? (2 Marks)

b) What is the velocity of section E in m/s? (2 Marks)

10.  How long would it take a truck to increase its speed from 10.0 m/s to 30.0 m/s if it does so with uniform acceleration over a distance of 80.0 m? (5 Marks)

vf2 = vi2 + 2ad a = (vf2 - vi2) ÷ 2d

a = (302 - 102) ÷ (2 x 80)

a = 5.00 m/s2

vf = vi + at

t = (vf - vi) ÷ a

t = (30 -10) ÷ 5.00

t = 4.0 s

11.  The following graph shows the velocity of an object versus time.

Using the graph find the following:

a)  The average acceleration of the object over the 16.0 s. (1 mark)

b)  The average velocity of the object between t = 6.00 s and t = 12.0 s. (1 marks)

c)  i) The distance traveled by the object after 8.00 s. (1 mark)

ii) The displacement of the object after 8.00 s. (1 mark)

iii) The displacement of the object after 12.0 s. (1 mark)

iv) The distance traveled by the object after 12.0 s. (1 mark)

d)  The equation for the line between t = 0 and t = 4.00 s. (2 marks)

e)  The equation for the line between t = 6.00 s and t = 12.0 s. (2 mark)

Mr. Marzouk 4 of 4