Combined Gas Law Answers Hints

Combined Gas Law answers hints

73. x = [ (300 torr) (800 mL) (500 K) ] / [ (250 K) (600 torr) ]; x = 800.0 mL

74. x = [ (700/760) (500) (293) ] / [ (473) (30) ]; x = 9.51 L

Note that this problem mixes pressure units. The 700/760 fraction converts mmHg to atm.

75. x = [ (760 mm Hg) (400 mL) (303 K) ] / [ (295 K) (360 mm Hg) ]; x = 867.3 mL

76. x = [ (0.25) (300) (200) ] / [ (400) (2) ]

77. x = [ (785) (45.5) (303) ] / [ (288) (745) ]

78. x = [ (800) (34.2) (273) ] / [ (288) (760) ]

79. x = [ (1) (488.8) (28) ] / [ (273) (100) ]

80. x = [ (780) (350) (273) ] / [ (297.2) (760) ]

81. x = [ (1.50 atm) (4.25 L) (297.5 K) ] / [(1825 mm Hg/760 atm mmHg-1) (3.25 L) ]

Note that we had to change units around somewhat. Also note that a temperature was solved for rather than the usual volume.

82. x = [ (760) (10) (785) ] / [ (273) (1520) ]

83. x = [ (3.00 atm) (720.0 mL) (273 K) ] / [ (293 K) (1.00 atm)

84. x = [ (3.50) (20) (298) ] / [ (750/760) (2.00) ]

85. x = [ (740 mmHg) (106 L) (293 K) ] / [ (318 K) (780 mmHg) ]

86. x = [ (1) (10) (2) ] / [ (1) (3) ]

87. x = [ (1.00 atm) (73.0 mL) (353 K) ] / [ (273 K) (4530 mL) ]

88. x = [ (720) (500) (273) ] / [ (293) (760) ]

89. x = [ (640) (50) (273) ] / [ (288) (760) ]

90. A gas is heated from 263.0 K to 298.0 K and the volume is increased from 24.0 liters to 35.0 liters by moving a large piston within a cylinder. If the original pressure was 1.00 atm, what would the final pressure be?

91. The pressure of a gas is reduced from 1200.0 mm Hg to 850.0 mm Hg as the volume of its container is increased by moving a piston from 85.0 mL to 350.0 mL. What would the final temperature be if the original temperature was 90.0 oC?

92. If a gas is heated from 298.0 K to 398.0 K and the pressure is increased from 2.230 x 103 mm Hg to 4.560 x 103 mm Hg what final volume would result if the volume is allowed to change from an initial volume of 60.0 liters?