Noel Sturm:Any Questions Before We Begin?Jun 10, 2010 10:02:01 AM PDT Sara Shirazi:Did

Noel Sturm:Any questions before we begin?Jun 10, 2010 10:02:01 AM PDT
Sara Shirazi:did you find out about how many questions are on the test?Jun 10, 2010 10:03:04 AM PDT
Paris Shoghi:yes 9a from ch.3: why is CuCl used instead of CuI?Jun 10, 2010 10:03:20 AM PDT
[Erika Perezjoined the session]Jun 10, 2010 10:03:58 AM PDT
Noel Sturm:Yes 29 questions all similar in format to the homework, work sheets and quick thinksJun 10, 2010 10:04:04 AM PDT
Noel Sturm:You can use either but stay with CuIJun 10, 2010 10:04:28 AM PDT
Paris Shoghi:ok, thanks.Jun 10, 2010 10:04:40 AM PDT
Noel Sturm:The answers for the monochlorination problem I gave you at the end of class yesterday are now on-lineJun 10, 2010 10:05:03 AM PDT
[Bryan Ohjoined the session]Jun 10, 2010 10:05:16 AM PDT
Noel Sturm:Go to the web site and take a look, I'll give you a couple of minutesJun 10, 2010 10:05:25 AM PDT
[Dhir Patelleft the session]Jun 10, 2010 10:05:32 AM PDT
Uche Ochia:Dr. Sturm the answers does not openJun 10, 2010 10:05:51 AM PDT
[Stephen Tonsongleft the session]Jun 10, 2010 10:05:53 AM PDT
Sara Shirazi:yeah, its not a hyperlinkJun 10, 2010 10:06:03 AM PDT
[Lauren Majoined the session]Jun 10, 2010 10:06:13 AM PDT
Noel Sturm:It is a .doc fileJun 10, 2010 10:06:23 AM PDT
Uche Ochia:Dr Sturm: The answers do not openJun 10, 2010 10:06:28 AM PDT
[Dhir Pateljoined the session]Jun 10, 2010 10:06:31 AM PDT
[Joseph Bellavialeft the session]Jun 10, 2010 10:06:53 AM PDT
[Joseph Bellaviajoined the session]Jun 10, 2010 10:06:58 AM PDT
Noel Sturm:If you are using an older version of MS Office you need to install a patch to view .docx filesJun 10, 2010 10:07:02 AM PDT
Beverly Pozuelos:It opened for me but as a .docxJun 10, 2010 10:07:06 AM PDT
Uche Ochia:ok..thxJun 10, 2010 10:07:16 AM PDT
[Lauren Maleft the session]Jun 10, 2010 10:07:18 AM PDT
[Stephen Tonsongjoined the session]Jun 10, 2010 10:07:32 AM PDT
[Joseph Bellavialeft the session]Jun 10, 2010 10:07:41 AM PDT
Noel Sturm:There are basically five structures, translation there are five unique "H"'s that we can replace with ClJun 10, 2010 10:07:51 AM PDT
Noel Sturm:Does this make sense?Jun 10, 2010 10:08:16 AM PDT
[Eugene Shinleft the session]Jun 10, 2010 10:08:20 AM PDT
[Gabriel Floresleft the session]Jun 10, 2010 10:08:23 AM PDT
Dhir Patel:yesJun 10, 2010 10:08:36 AM PDT
Dhir Patel:thank youJun 10, 2010 10:08:40 AM PDT
[Eugene Shinjoined the session]Jun 10, 2010 10:08:41 AM PDT
Paris Shoghi:can you explain the third structure? how is that C unique?Jun 10, 2010 10:08:51 AM PDT
Elisa Harry:will there be only problems that you have to work out, or will there also be questions that ask you to give definitions or naming rules?Jun 10, 2010 10:08:54 AM PDT
[Gabriel Floresjoined the session]Jun 10, 2010 10:08:54 AM PDT
[Aikoui Ohanyanjoined the session]Jun 10, 2010 10:08:56 AM PDT
[Lauren Majoined the session]Jun 10, 2010 10:09:00 AM PDT
Noel Sturm:We are going to begin StereochemistryJun 10, 2010 10:09:11 AM PDT
[Dhir Patelleft the session]Jun 10, 2010 10:09:23 AM PDT
[Dhir Pateljoined the session]Jun 10, 2010 10:09:33 AM PDT
[Joseph Bellaviajoined the session]Jun 10, 2010 10:09:37 AM PDT
Noel Sturm:So unlike isomers which are different compounds with the same molecular formula, structural isomers differ in which atoms are bonded to which atomsJun 10, 2010 10:10:24 AM PDT
Noel Sturm:The simplest form, Slide 3, are cis trans, note cis the methyl groups are on the same side of the double bondJun 10, 2010 10:11:06 AM PDT
Noel Sturm:trans they are on opposite sidesJun 10, 2010 10:11:15 AM PDT
Sara Shirazi:so they are different compounds when they have cis or trans relationships?Jun 10, 2010 10:12:08 AM PDT
Noel Sturm:The concept of optical activity or (+), (-), (d), (l) is something that must be determined in the lab using a polarimeterJun 10, 2010 10:12:12 AM PDT
[Elisa Harryleft the session]Jun 10, 2010 10:12:24 AM PDT
Noel Sturm:I.E. measuring the angle of rotation of polarized lightJun 10, 2010 10:12:39 AM PDT
Sara Shirazi:so they are different compounds when they have cis or trans relationships?Jun 10, 2010 10:12:54 AM PDT
Noel Sturm:However the concept of (R) and (S) configuration is something we can do on paperJun 10, 2010 10:13:23 AM PDT
Noel Sturm:So configurations are the arrangement of groups about a chiral centerJun 10, 2010 10:13:56 AM PDT
Noel Sturm:a chiral center is most simply defined as a carbon with four "differnt" groups attached to itJun 10, 2010 10:14:31 AM PDT
Beverly Pozuelos:Sorry are we on slide 7 now?Jun 10, 2010 10:14:34 AM PDT
Noel Sturm:Yes cis and trans have different properties but the sme molecular formulaJun 10, 2010 10:15:04 AM PDT
Sara Shirazi:thank youJun 10, 2010 10:15:17 AM PDT
Noel Sturm:slide 10, we can draw "configurations" in two ways to show spacial arrangementJun 10, 2010 10:15:56 AM PDT
Noel Sturm:using wedges or Fischer projectionsJun 10, 2010 10:16:09 AM PDT
[Elisa Harryjoined the session]Jun 10, 2010 10:16:11 AM PDT
Noel Sturm:We will focus on Fischer projectionsJun 10, 2010 10:16:20 AM PDT
Stephen Tonsong:Why the primary alcohol on the right.there seems to be no chiral carbon slid 9Jun 10, 2010 10:16:42 AM PDT
[Dorothy Ojimbajoined the session]Jun 10, 2010 10:17:41 AM PDT
Noel Sturm:Notice in slide 11 that the translation of a wedge diagram to a Fischer projection is that the atoms on the horizontal plane are "hugging" youJun 10, 2010 10:17:42 AM PDT
Noel Sturm:i.e. coming out of the paper towards youJun 10, 2010 10:17:54 AM PDT
Noel Sturm:vertical are going back into the paperJun 10, 2010 10:18:05 AM PDT
Noel Sturm:It is achiralJun 10, 2010 10:18:46 AM PDT
Noel Sturm:so let's practice recognizing if a molecule is chiralJun 10, 2010 10:19:01 AM PDT
Noel Sturm:that is the first stepJun 10, 2010 10:19:09 AM PDT
Noel Sturm:so draw 3-bromohexane and tell me if it is chiralJun 10, 2010 10:19:41 AM PDT
Noel Sturm:then 3-chloro-3-methylpentaneJun 10, 2010 10:20:01 AM PDT
Noel Sturm:1,2-dibromo-2-methylbutaneJun 10, 2010 10:20:26 AM PDT
Joseph Bellavia:ChiralJun 10, 2010 10:21:19 AM PDT
Joseph Bellavia:for 3 bromohexaneJun 10, 2010 10:21:38 AM PDT
Stephen Tonsong:3-bromo ischira,but 3 chloro is notJun 10, 2010 10:21:56 AM PDT
Noel Sturm:CH3CH2*CH(Br)CH2CH2CH3Jun 10, 2010 10:22:04 AM PDT
Noel Sturm:The chiral carbon is marked with a *Jun 10, 2010 10:22:19 AM PDT
Noel Sturm:so 3-bromohexane is chiralJun 10, 2010 10:22:28 AM PDT
Dorothy Ojimba:IS THE chiral the teritiary carbonJun 10, 2010 10:22:48 AM PDT
Noel Sturm:3-chloro-3-methylpentane is not chiral because of symetryJun 10, 2010 10:22:52 AM PDT
Paris Shoghi:are we talking about chiral as in not superimposable or chiral center?Jun 10, 2010 10:23:02 AM PDT
[Brenda Guzmanjoined the session]Jun 10, 2010 10:23:25 AM PDT
Noel Sturm:BrCH2*C(Br)(CH3)Ch2CH3Jun 10, 2010 10:23:30 AM PDT
Stephen Tonsong:1,2-dibro is chiralJun 10, 2010 10:23:32 AM PDT
Noel Sturm:1,2-dibromo-2-methylbutane is chiralJun 10, 2010 10:23:44 AM PDT
Noel Sturm:We are talking simply is there a carbon with four unique (different) groups attached to itJun 10, 2010 10:24:23 AM PDT
Dorothy Ojimba:Is the ethyl and methyl group categorize as different ?Jun 10, 2010 10:25:04 AM PDT
Noel Sturm:YesJun 10, 2010 10:25:14 AM PDT
Dhir Patel:isnt 1,2 dibromo achiral because the central carbon is attached to two ch2 groupsJun 10, 2010 10:25:28 AM PDT
Dhir Patel:which would mean that it doesnt have four unique atomsJun 10, 2010 10:25:41 AM PDT
Dorothy Ojimba:so can we say the chrial is the teriary carbon?Jun 10, 2010 10:25:56 AM PDT
Stephen Tonsong:so the other compound on slide # was not a chira compoundJun 10, 2010 10:25:58 AM PDT
Noel Sturm:once we have a chiral carbon we can draw a Fischer projection where the chiral carbon is represented at the intersection of the vertical and horizontal linesJun 10, 2010 10:26:08 AM PDT
Noel Sturm:The alcohol on slide 9 is not chiral it is achiralJun 10, 2010 10:26:49 AM PDT
[Brenda Guzmanleft the session]Jun 10, 2010 10:26:52 AM PDT
Stephen Tonsong:thanks.i was surprisedJun 10, 2010 10:27:13 AM PDT
Noel Sturm:This has nothing to do with primary, secondary tertiaryJun 10, 2010 10:27:14 AM PDT
Dhir Patel:can you look at the third example you gave us. why is it chiral?Jun 10, 2010 10:27:15 AM PDT
[Erika Perezleft the session]Jun 10, 2010 10:27:22 AM PDT
Dhir Patel:because it has two ch2 groups attached to the central carbon, wouldnt that be achiral:Jun 10, 2010 10:27:30 AM PDT
Noel Sturm:The chiral caron has a BrCH2, Br, CH3, CH2CH3 attached to itJun 10, 2010 10:27:50 AM PDT
[Raven Beanleft the session]Jun 10, 2010 10:28:07 AM PDT
Dhir Patel:ohh i see so you have to account for the whole chain?Jun 10, 2010 10:28:12 AM PDT
Noel Sturm:yesJun 10, 2010 10:28:19 AM PDT
Dhir Patel:okay thank youJun 10, 2010 10:28:22 AM PDT
Dorothy Ojimba:So in slide 9, why is the one with alcohol not a chiral?Jun 10, 2010 10:28:43 AM PDT
Leslie-Ann Go:i think it's attached to ch2 and an ethylJun 10, 2010 10:28:45 AM PDT
Aaron Uehara:yeaJun 10, 2010 10:28:59 AM PDT
Dhir Patel:because it has two hydrogens on the top and bottomJun 10, 2010 10:29:17 AM PDT
Noel Sturm:There is no carbon with four different groups attached to itJun 10, 2010 10:29:22 AM PDT
[Erika Perezjoined the session]Jun 10, 2010 10:29:50 AM PDT
Dorothy Ojimba:it have 2 methyl group, i ethyl, and an alcoholJun 10, 2010 10:29:52 AM PDT
Noel Sturm:Draw it out looking at each carbonJun 10, 2010 10:29:59 AM PDT
Stephen Tonsong:the carbon is attached to two methyl gpJun 10, 2010 10:30:14 AM PDT
Noel Sturm:So the R/S systemJun 10, 2010 10:30:31 AM PDT
Noel Sturm:Once we draw a Fischer projection, slide 15, we need to be able to prioritize the four groups attached to the chiral carbonJun 10, 2010 10:31:25 AM PDT
[Raven Beanjoined the session]Jun 10, 2010 10:31:38 AM PDT
Noel Sturm:Hence slide 14 the "rules"Jun 10, 2010 10:31:47 AM PDT
Noel Sturm:much easier to look at the rules using examples so back to slide 15Jun 10, 2010 10:32:17 AM PDT
Noel Sturm:top left compoundJun 10, 2010 10:32:28 AM PDT
Noel Sturm:Br is a higher priority than Cl because of atomic numberJun 10, 2010 10:32:50 AM PDT
Noel Sturm:Cl higher than FJun 10, 2010 10:33:01 AM PDT
[Sohee Ahnleft the session]Jun 10, 2010 10:33:09 AM PDT
Noel Sturm:and H, no mater what molecule will always be lowestJun 10, 2010 10:33:18 AM PDT
Noel Sturm:compound upper rightJun 10, 2010 10:33:33 AM PDT
Noel Sturm:O has a higher atomic number than C so OH is number 1Jun 10, 2010 10:33:52 AM PDT
Noel Sturm:then CH2Br is number two because of the Br then CH3Jun 10, 2010 10:34:16 AM PDT
Noel Sturm:and last as always HJun 10, 2010 10:34:26 AM PDT
Noel Sturm:last compoundJun 10, 2010 10:34:32 AM PDT
Dorothy Ojimba:do we calculate the oxygen atomic number and the hydrogen togetherJun 10, 2010 10:34:43 AM PDT
Noel Sturm:Br is number one, higher atomic number than CJun 10, 2010 10:34:47 AM PDT
Noel Sturm:CH=VH2, double bond always higher priority than single bond so number 2Jun 10, 2010 10:35:16 AM PDT
Noel Sturm:then CH2CH3 and last HJun 10, 2010 10:35:26 AM PDT
Noel Sturm:Now, as always, the only way to "get" this is to practiceJun 10, 2010 10:35:55 AM PDT
Noel Sturm:So let me sat a few words about R/S firstJun 10, 2010 10:36:18 AM PDT
Noel Sturm:Once we label the groups 1 through 4 than simply draw an aroow moving from 1 --> 2 -->3 -->4Jun 10, 2010 10:37:00 AM PDT
Noel Sturm:If the arrow goes clockwise it is RJun 10, 2010 10:37:20 AM PDT
Noel Sturm:counterclockwise is SJun 10, 2010 10:37:33 AM PDT
Noel Sturm:Slide 17Jun 10, 2010 10:37:43 AM PDT
Dorothy Ojimba:clockwise means rightJun 10, 2010 10:37:54 AM PDT
Dorothy Ojimba:couner clockwise does it mean leftJun 10, 2010 10:38:16 AM PDT
Noel Sturm:The one thing you must do however is make sure that group number 4 is rotated away from you, slide 18Jun 10, 2010 10:38:53 AM PDT
Eugene Shin:away as into the paper?Jun 10, 2010 10:39:17 AM PDT
Noel Sturm:So when priority #4 ends up on the vertical you can read it directlyJun 10, 2010 10:39:24 AM PDT
Noel Sturm:when priority #4 is on the horizonal you must rotate it backJun 10, 2010 10:39:46 AM PDT
Dhir Patel:on slide 19, after pushing the hydrogen back, how do you know if F will be placed left or right in order to find out the R or S sequence?Jun 10, 2010 10:39:56 AM PDT
Noel Sturm:Now is when models can really help youJun 10, 2010 10:40:03 AM PDT
Noel Sturm:Give the different colored balls dirrent priorities, i.e. red could be #1, blue #2 etcJun 10, 2010 10:40:35 AM PDT
Noel Sturm:You have to picture it three dimensionallyJun 10, 2010 10:41:00 AM PDT
Noel Sturm:If you can't see it immediately on paper use modelsJun 10, 2010 10:41:16 AM PDT
Michael Reich:Can we use models on the test?Jun 10, 2010 10:42:04 AM PDT
[Joseph Bellavialeft the session]Jun 10, 2010 10:42:04 AM PDT
Noel Sturm:Yes you can use models during examsJun 10, 2010 10:42:16 AM PDT
Noel Sturm:Now before I put up the quick think I want to run through the remainder of the slidesJun 10, 2010 10:42:50 AM PDT
Sara Shirazi:so if #4 is coming at you, you flip your result. so if it was R, then it would really be S?Jun 10, 2010 10:42:53 AM PDT
[Joseph Bellaviajoined the session]Jun 10, 2010 10:43:02 AM PDT
Dhir Patel:oohhhh i ge titJun 10, 2010 10:43:11 AM PDT
Dhir Patel:get it*Jun 10, 2010 10:43:20 AM PDT
Noel Sturm:Don't appraoch it that way, take each case and work it outJun 10, 2010 10:43:22 AM PDT
Noel Sturm:You can understand the remainder of the sldies which have to do with reactions of chiral and achiral compounds byJun 10, 2010 10:44:00 AM PDT
[Joseph Bellavialeft the session]Jun 10, 2010 10:44:58 AM PDT
[Joseph Bellaviajoined the session]Jun 10, 2010 10:45:02 AM PDT
Noel Sturm:looking at the answers, the five compounds, generated from the monochlorination of 1-cholor-2-methylbutaneJun 10, 2010 10:45:04 AM PDT
Noel Sturm:Before Tuesday dteremine whether each of the products you generated is chiral or achiral, also determine if a new chiral center is formedJun 10, 2010 10:46:05 AM PDT
Noel Sturm:Note that the starting molecule 1-chloro-2-mthylbutane is chiralJun 10, 2010 10:46:32 AM PDT
Noel Sturm:We will then discuss your results on TuesdayJun 10, 2010 10:47:02 AM PDT
Noel Sturm:Let me point out that there is a program that will generate thousands of R/S practice problems on the web, use internet explorer, slide 19Jun 10, 2010 10:48:09 AM PDT
Noel Sturm:So I am going to make a link on the web site to the Quick Think under the Stereochemistry work sheetJun 10, 2010 10:48:54 AM PDT
[Raven Beanleft the session]Jun 10, 2010 10:49:16 AM PDT
Noel Sturm:So first thing is prioritize the groups on each of the Fischer projectionsJun 10, 2010 10:50:38 AM PDT
Noel Sturm:Take a few minutes to do thisJun 10, 2010 10:51:36 AM PDT
[Sara Shirazileft the session]Jun 10, 2010 10:52:34 AM PDT
[Joseph Bellavialeft the session]Jun 10, 2010 10:52:39 AM PDT
[Joseph Bellaviajoined the session]Jun 10, 2010 10:52:48 AM PDT
[Sara Shirazijoined the session]Jun 10, 2010 10:52:50 AM PDT
[Joseph Bellavialeft the session]Jun 10, 2010 10:52:54 AM PDT
Noel Sturm:Then determine if goup #4 is on the vertical or horizontalJun 10, 2010 10:53:17 AM PDT
[Aikoui Ohanyanleft the session]Jun 10, 2010 10:53:33 AM PDT
Dorothy Ojimba:so how we do we label it like 2R, or 2SJun 10, 2010 10:53:36 AM PDT
Noel Sturm:NoJun 10, 2010 10:53:44 AM PDT
Noel Sturm:In the Quick Think give each group on each of the Fischer projections priority numbers 1-4Jun 10, 2010 10:54:37 AM PDT
Stephen Tonsong:on slide 20 why do we use R with a series of negatives and S with negatives and positivesJun 10, 2010 10:54:50 AM PDT
Noel Sturm:Let me know how you are coming.Jun 10, 2010 10:54:51 AM PDT
[Aikoui Ohanyanjoined the session]Jun 10, 2010 10:54:51 AM PDT
Dorothy Ojimba:OH i was too fastJun 10, 2010 10:54:58 AM PDT
Noel Sturm:don't worry about the (+) and (-) they are experimentally determined based on rotation of polarized lightJun 10, 2010 10:55:47 AM PDT
Noel Sturm:Do you have all of the groups prioritized?Jun 10, 2010 10:56:21 AM PDT
[Joseph Bellaviajoined the session]Jun 10, 2010 10:56:57 AM PDT
Stephen Tonsong:so does it mean the 1-chloro-2-methylbutane is RJun 10, 2010 10:57:07 AM PDT
Beverly Pozuelos:yesJun 10, 2010 10:57:08 AM PDT
Noel Sturm:Yes/no?Jun 10, 2010 10:57:13 AM PDT
Gabriel Flores:yesJun 10, 2010 10:57:27 AM PDT
Eugene Shin:yupJun 10, 2010 10:57:41 AM PDT
Noel Sturm:No just chiralJun 10, 2010 10:57:43 AM PDT
Leslie-Ann Go:what slide are we on?Jun 10, 2010 10:57:47 AM PDT
Noel Sturm:you can drawthe R/S configurationsJun 10, 2010 10:57:57 AM PDT
[Zahra Hooshyarleft the session]Jun 10, 2010 10:57:57 AM PDT
[Zahra Hooshyarjoined the session]Jun 10, 2010 10:58:06 AM PDT
Noel Sturm:We are working on the Quick ThinkJun 10, 2010 10:58:11 AM PDT
Joseph Bellavia:noJun 10, 2010 10:59:31 AM PDT
Leslie-Ann Go:is it on the worksheet?Jun 10, 2010 10:59:35 AM PDT
Stephen Tonsong:it seems as if changing the positions of the groups changes the configurationJun 10, 2010 10:59:41 AM PDT
Noel Sturm:Yes you can not do thatJun 10, 2010 10:59:57 AM PDT
Noel Sturm:First molecule: SO3H 1, OCH3 2, N(CH3)2 3 and H 4Jun 10, 2010 11:01:15 AM PDT
Noel Sturm:Make sense?Jun 10, 2010 11:01:23 AM PDT
Beverly Pozuelos:yesJun 10, 2010 11:01:46 AM PDT
Michael Reich:yesJun 10, 2010 11:01:50 AM PDT
Gabriel Flores:so its SJun 10, 2010 11:01:56 AM PDT
Noel Sturm:Now note that H is on the vertical so we can draw our arrow 1-->2-->3-->4 directlyJun 10, 2010 11:01:57 AM PDT
Noel Sturm:counterclockwise, SJun 10, 2010 11:02:55 AM PDT
Noel Sturm:Make sense?Jun 10, 2010 11:03:03 AM PDT
Beverly Pozuelos:wait, sorry I misread the numbersJun 10, 2010 11:03:57 AM PDT
Beverly Pozuelos:why is H2CO higher priority than N(ch3)2Jun 10, 2010 11:04:08 AM PDT
Beverly Pozuelos:*H3CO > N(CH3)2Jun 10, 2010 11:04:27 AM PDT
Noel Sturm:Second molecule: Cl 1, OCH3 2, OH 3, CO2CH3 4Jun 10, 2010 11:04:31 AM PDT
Noel Sturm:Atomic numbersJun 10, 2010 11:04:45 AM PDT
Noel Sturm:now the priority 4 group is on the horizontal so we must rotate it backJun 10, 2010 11:05:15 AM PDT
Noel Sturm:when we do that 1-->2-->3 is clockwise RJun 10, 2010 11:05:59 AM PDT
[Raven Beanjoined the session]Jun 10, 2010 11:06:05 AM PDT
Noel Sturm:Yes no??Jun 10, 2010 11:06:20 AM PDT
Dhir Patel:sorry i have been trying to look for the quick think, where is it?Jun 10, 2010 11:06:21 AM PDT
Noel Sturm:maybe?Jun 10, 2010 11:06:25 AM PDT
Noel Sturm:You may need modelsJun 10, 2010 11:06:32 AM PDT
Leslie-Ann Go:it's a link under worksheets on the websiteJun 10, 2010 11:06:43 AM PDT
Paris Shoghi:how did you get clockwise?Jun 10, 2010 11:06:45 AM PDT
Leslie-Ann Go:but mine won't let me click itJun 10, 2010 11:06:49 AM PDT
Noel Sturm:Syllabus, below the stereochemistry work sheetJun 10, 2010 11:06:55 AM PDT
Noel Sturm:Rotate 4 back then 1-->2-->3 is clockwiseJun 10, 2010 11:07:25 AM PDT
Leslie-Ann Go:could you maybe post the link again?Jun 10, 2010 11:07:31 AM PDT
Sara Shirazi:mine opens up as a blank document..Jun 10, 2010 11:07:34 AM PDT
Leslie-Ann Go:b/c i can't click on it, it's just thereJun 10, 2010 11:07:43 AM PDT
Sara Shirazi:or scan and email?Jun 10, 2010 11:07:46 AM PDT
Noel Sturm:You have to figure out how to open .dcox files on your computerJun 10, 2010 11:07:55 AM PDT
Noel Sturm:refresh your browserJun 10, 2010 11:08:18 AM PDT
Leslie-Ann Go:thank you!Jun 10, 2010 11:08:36 AM PDT
Joseph Bellavia:I have leaving CO2CH3 on the horizontal, then when I rotate 4 back I get S, not RJun 10, 2010 11:08:55 AM PDT
Stephen Tonsong:Dr,sturn just giving us the name of the compound makes it easier for us to draw and figure it cos the one up i can't identify the chiral carbonJun 10, 2010 11:09:10 AM PDT
Dorothy Ojimba:i cannot open the fileJun 10, 2010 11:09:11 AM PDT
Noel Sturm:Last molecule: NO2 1, CO2H 2, CH2CH3 3, H 4Jun 10, 2010 11:09:33 AM PDT
Noel Sturm:No just giving the name leaves a lot of ambiguity on how to draw the Fischer projectionJun 10, 2010 11:10:06 AM PDT
Stephen Tonsong:i have not been able to open the file cos i have to follow up the classJun 10, 2010 11:10:09 AM PDT
Beverly Pozuelos:Does that mean we won't be expected to know how to draw a Fischer projection based on the name on the tests?Jun 10, 2010 11:10:57 AM PDT
Noel Sturm:rotate #4 back and moving from 1-->2-->3 is counterclockwise SJun 10, 2010 11:11:15 AM PDT
Noel Sturm:yesJun 10, 2010 11:11:24 AM PDT
Stephen Tonsong:yes ,Jun 10, 2010 11:11:40 AM PDT
Noel Sturm:but you should be able to give the condensed formula from the Fischer projectionJun 10, 2010 11:12:02 AM PDT
Paris Shoghi:so I'm using my model but I'm confused...why is it counterclockwise?Jun 10, 2010 11:12:09 AM PDT
Beverly Pozuelos:Ok, thanks Dr. SturmJun 10, 2010 11:12:35 AM PDT
Joseph Bellavia:can you show me the priority for the third molecule, Im doing something wrongJun 10, 2010 11:12:44 AM PDT
Joseph Bellavia:1>HO3S,2>H3C0, 3>N(CH3), 4>H...?Jun 10, 2010 11:14:06 AM PDT
Noel Sturm:I just posted the answer ket so take a look at how I worked them out on paper, then hold the model up and try to see itJun 10, 2010 11:14:24 AM PDT
Stephen Tonsong:from the last question ,i figured out how u draw the structure, so the condense formular is not a problemJun 10, 2010 11:14:57 AM PDT
Noel Sturm:I'm afraid this will just take a lot of practice so use the web link (use Internet Explorer) and do a lot of theseJun 10, 2010 11:15:04 AM PDT
[Raven Beanleft the session]Jun 10, 2010 11:15:27 AM PDT
Dorothy Ojimba:my computer can not open the quick thinkJun 10, 2010 11:16:02 AM PDT
[Aikoui Ohanyanleft the session]Jun 10, 2010 11:16:19 AM PDT
Noel Sturm:You need to figure out how to open .docx files by down loading a patch for older versions of MS officeJun 10, 2010 11:16:44 AM PDT
Dorothy Ojimba:okJun 10, 2010 11:17:18 AM PDT
Noel Sturm:Now how about questions on material for Exam 1?Jun 10, 2010 11:17:22 AM PDT
Sara Shirazi:how detailed should we know the reactive intermediates?Jun 10, 2010 11:18:21 AM PDT
Noel Sturm:Chapters 1-3Jun 10, 2010 11:18:24 AM PDT
Noel Sturm:Again there are 29 questions on the examJun 10, 2010 11:18:45 AM PDT
Michael Reich:Dr. Sturm, are the horizontals always "hugging" us for every R/S question?Jun 10, 2010 11:19:19 AM PDT
Noel Sturm:For now just the free radical and understand the order 3>2>1>CH3Jun 10, 2010 11:19:22 AM PDT
Paris Shoghi:is it all solving problems or are there also questions requiring us to define terms, etc?Jun 10, 2010 11:19:38 AM PDT
Stephen Tonsong:is there a rule to know the #of isomers formed from a giving compoundsJun 10, 2010 11:19:46 AM PDT
Joseph Bellavia:How do we know, when drawing isohexane that the branched carbon comes off of a 2 carbon and not in the middle of the longest chain?Jun 10, 2010 11:19:50 AM PDT
Noel Sturm:Yes horizontal always hugging, it is the convention for Fischer projectionsJun 10, 2010 11:19:51 AM PDT
Michael Reich:That makes alot easier, thanks.Jun 10, 2010 11:20:06 AM PDT
Noel Sturm:memorize iso, sec, tJun 10, 2010 11:20:16 AM PDT
Joseph Bellavia:okJun 10, 2010 11:21:21 AM PDT
Sara Shirazi:is iso sec and t only for butane?Jun 10, 2010 11:21:50 AM PDT
Noel Sturm:Yes there is a rule for number of isomers but don't worry about it just know the number of isomers for methane throughhexaneJun 10, 2010 11:21:58 AM PDT
Dhir Patel:ok thanksJun 10, 2010 11:22:16 AM PDT
Zahra Hooshyar:is there any essay questionJun 10, 2010 11:22:28 AM PDT
Noel Sturm:isopropylJun 10, 2010 11:22:58 AM PDT
Stephen Tonsong:will it be accepted if one name isopropyl bromide as 2-bromopropaneJun 10, 2010 11:22:59 AM PDT
Dhir Patel:so you dont want us using the names t-butyl or s-butyl on the test, and instead use IUPAC right?Jun 10, 2010 11:23:03 AM PDT
Noel Sturm:isohexane, neohexaneJun 10, 2010 11:23:10 AM PDT
Dhir Patel:nevermindJun 10, 2010 11:23:36 AM PDT
Noel Sturm:you would use t-butyl and sec-butyl to name alkyl substituents on a parent chainJun 10, 2010 11:23:57 AM PDT
[John Shepherdleft the session]Jun 10, 2010 11:24:32 AM PDT
Noel Sturm:the format of the exam is similar to the work sheets, homework and quick thinksJun 10, 2010 11:24:48 AM PDT
Gabriel Flores:so the t in t-butyl and s in sec-butyl do no count when alphabetizingJun 10, 2010 11:25:29 AM PDT
Navreena Sahota:will we be tested on material in the book that you havent lectured? or should we just concentrate on the information you lectured on?Jun 10, 2010 11:25:45 AM PDT
Noel Sturm:correctJun 10, 2010 11:25:47 AM PDT
Gabriel Flores:thanksJun 10, 2010 11:25:59 AM PDT
Noel Sturm:the T and s don't countJun 10, 2010 11:26:02 AM PDT
Navreena Sahota:will we be tested on material in the book that you havent lectured about? or should we only concentrate on the information you lectured on?Jun 10, 2010 11:28:24 AM PDT
Noel Sturm:just lecture materialJun 10, 2010 11:29:04 AM PDT
Navreena Sahota:ok thank you!Jun 10, 2010 11:29:13 AM PDT
Stephen Tonsong:does it mean the lecture for today is overJun 10, 2010 11:30:30 AM PDT
Dhir Patel:hahahaJun 10, 2010 11:30:51 AM PDT
Aaron Uehara:hahahahaJun 10, 2010 11:31:00 AM PDT
Noel Sturm:So I am going to sign off and see you MondayJun 10, 2010 11:31:03 AM PDT
Dhir Patel:THANK YOUJun 10, 2010 11:31:10 AM PDT
Navreena Sahota:thank you bye!Jun 10, 2010 11:31:15 AM PDT
Dorothy Ojimba:Thank uJun 10, 2010 11:31:18 AM PDT
Zahra Hooshyar:Thank youJun 10, 2010 11:31:21 AM PDT
Eugene Shin:thanksJun 10, 2010 11:31:26 AM PDT
Aaron Uehara:thanksJun 10, 2010 11:31:29 AM PDT
Gabriel Flores:thanksJun 10, 2010 11:31:32 AM PDT
Leslie-Ann Go:thanksJun 10, 2010 11:31:33 AM PDT
Noel Sturm:After the exam on Monday go back to focusing on stereochemistryJun 10, 2010 11:31:38 AM PDT
Beverly Pozuelos:Have a good weekend!Jun 10, 2010 11:31:39 AM PDT
Stephen Tonsong:Dr i emailed u some questions yester