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Paired samples t-test on LITTORAL1 vs PELAGIC1 with 15 cases
Alternative = 'not equal'
Mean LITTORAL1 = 242.311
Mean PELAGIC1 = 1.711
Mean difference = 240.600
95.00% CI = -20.360 to 501.560
SD of difference = 471.232
t = 1.977
df = 14
p-value = 0.068 = as you can see littoral zone 1 is not significantly different than pelagic zone 1 (critical P value with 95% confidence is <0.05)
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Paired samples t-test on LITTORAL1 vs PELAGIC2 with 15 cases
Alternative = 'not equal'
Mean LITTORAL1 = 242.311
Mean PELAGIC2 = 2.267
Mean difference = 240.044
95.00% CI = -21.086 to 501.175
SD of difference = 471.541
t = 1.972
df = 14
p-value = 0.069 = as you can see littoral zone 1 is not significantly different than pelagic zone 2 (critical P value with 95% confidence is <0.05)
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Paired samples t-test on LITTORAL1 vs LITTORAL2 with 16 cases
Alternative = 'not equal'
Mean LITTORAL1 = 227.167
Mean LITTORAL2 = 199.750
Mean difference = 27.417
95.00% CI = -257.406 to 312.240
SD of difference = 534.515
t = 0.205
df = 15
p-value = 0.840 = as you can see littoral zone 1 is not significantly different than Littoral zone 2 (critical P value with 95% confidence is <0.05)
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Paired samples t-test on LITTORAL2 vs PELAGIC1 with 15 cases
Alternative = 'not equal'
Mean LITTORAL2 = 213.067
Mean PELAGIC1 = 1.711
Mean difference = 211.356
95.00% CI = -190.830 to 613.541
SD of difference = 726.253
t = 1.127
df = 14
p-value = 0.279 = as you can see littoral zone 2 is not significantly different than pelagic zone 1 (critical P value with 95% confidence is <0.05)
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Paired samples t-test on LITTORAL2 vs PELAGIC2 with 15 cases
Alternative = 'not equal'
Mean LITTORAL2 = 213.067
Mean PELAGIC2 = 2.267
Mean difference = 210.800
95.00% CI = -191.489 to 613.089
SD of difference = 726.440
t = 1.124
df = 14
p-value = 0.280 = as you can see littoral zone 2 is not significantly different than pelagic zone 2 (critical P value with 95% confidence is <0.05)
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Paired samples t-test on PELAGIC1 vs PELAGIC2 with 15 cases
Alternative = 'not equal'
Mean PELAGIC1 = 1.711
Mean PELAGIC2 = 2.267
Mean difference = -0.556
95.00% CI = -1.708 to 0.597
SD of difference = 2.080
t = -1.034
df = 14
p-value = 0.319 = as you can see pelagic zone 2 is not significantly different than pelagic zone 1 (critical P value with 95% confidence is <0.05)
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I did some paired ttests in systat using the means for the groups…so I used littoral zone 1 means vs. littoral zone 2 means etc. littoral zone 1 may have been significantly different than the pelagic zones given a 90% confidence interval…but as you all no 95% is kinda the standard with basic science so no cigar I suppose
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