Chapter 10 Chemical Reactions

Section #1: Simple Balancing

Steps for balancing:

1. Since these are written in symbol form, DO NOT mess with the subscripts.

2. Place Co-efficients IN FRONT of elements and/or compounds. NEVER in between compounds. Example: 2H2O is correct. H22O is not correct.)

3. Balance both sides so that you have the same number of elements on the reactants side as on the products side

1.HgO  Hg + O2

2.H2 O  H2 + O2

3.Al + Pb (NO3) 2  Al(NO3) 3 + Pb

4.Cu + AgNO3  Cu(NO3) 2 + Ag

5.K + H2O  KOH + H2

6.Cl2 + LiI  LiCl + I2

7.F2 + H2O  HF + O2

8.AgNO3 + K2SO4 Ag2SO4 +KNO3

9.Na + Cl2 NaCl

10. CaO + H2O  Ca(OH) 2

11. Mg + O2 MgO

12.Fe + O2 Fe2O3

13.H2O + N2O3 HNO2

14. Na2O + H2O  NaOH

15.Fe + H2O  Fe3O4 + H2

Section #2: Names into Symbols, then balance

Write and Balance equations for the following chemical reactions

Steps for balancing:

1. Change the names into symbols.

2. Remember, names ending in –ide are monoatomic ions. (Except for hydroxide and cyanide). Names ending in –ate or –ite are polyatomic ions.

3. Don’t forget your seven diatomic atoms (H2, N2, O2, F2, Cl2, Br2, I2)

4. Write the oxidation numbers for each element ABOVE the element so that you can balance the charges within the compound. Remember, if an element stands “alone”, its oxidation number plays no role until it is combined with another element (for example, Al is +3, but when it is alone, the +3 doesn’t do anything. But, when you put Al together with Cl, it becomes AlCl3).

5. Remember that the roman numerals tell you the POSITIVE oxidation number of the first element in the compound. Example: Copper (II) Nitrate means that copper has a +2 oxidation state. ALSO, if there is a Roman numeral but you expect the oxidation state to be different, go with the Roman numeral. Example: Nitrogen (II) Oxide. I know that you think nitrogen should be –3 from the chart, but the (II) makes it +2.

6. Once you have all of your subscripts in place, balance with co-efficients.

1.Magnesium Bromide + Chlorine  Magnesium chloride + Bromine

2.Chlorine + Sodium Iodide  Sodium Chloride + iodine

3.Aluminum Nitrate + Sodium Hydroxide  Aluminum hydroxide + sodium nitrate

4. Sulfur trioxide  sulfur dioxide + oxygen

(Sulfur trioxide is: SO3 , sulfur dioxide is: SO2)

5. Aluminum hydroxide + Iron  Iron (II) hydroxide + Aluminum

6.Ammonium nitrite  nitrogen + water

(Ammonium is: NH4+and ammonia is: NH3)

7. Silver(I)Chloride + Aluminum Sulfate  Aluminum Chloride + Silver Sulfate

8.Barium Chloride + sodium sulfate  sodium chloride + barium sulfate

9. Iron (III) oxide + carbon monoxide  iron + carbon dioxide

10.Aluminum + Copper (II) chloride  aluminum chloride + copper

11.Iron + silver (I) acetate  iron (II) acetate + silver

Textbook Helpful Sections

P. 290 Table 10-2 has guidelines for Double-Replacement Reactions

Section #3: Combustion Reactions (p. 285)

Steps for Balancing Combustion Reactions:

1. Balance the C’s and the H’s First.

2. Write a fraction in front of the O2 on the reactant’s side such that the numerator of the fraction is equal to the number of oxygen’s you need divided by 2. Example: For question #1, you will write 7/2O2.

3. Multiply the entire equation through by 2

1. C2H6 + O2 ------ CO2 + H2O

2. C4H10 + O2 ------ CO2 + H2O

3. C6H14 + O2 ------ CO2 + H2O

4. C8H18 + O2 ------ CO2 + H2O

5. C10H22 + O2 ------ CO2 + H2O

6. CH3OH + O2 ------ CO2 + H2O

7. C2H5OH + O2 ------ CO2 + H2O

8. C3H7OH + O2 ------ CO2 + H2O

9. C4H9OH + O2 ------ CO2 + H2O

10. C5H11OH + O2 ------ CO2 + H2O

Section #4: Predict the Products (p. 291)

Balance and predict the products

Textbook Helpful Sections

P. 291 Table 10-3 has How to Predict Products of a Chemical Reaction

1.Aluminum + hydrochloric acid 

2.Iron + copper (II) sulfate  (iron II compound is formed).

3. Chlorine + magnesium iodide 

4.Magnesium + hydrochloric acid 

5. Magnesium + oxygen 

6.Iron metal + oxygen  (an Iron (III) compound is formed)

7.Iron (II) sulfide + hydrochloric acid 

8.Ammonium sulfide + iron (II) nitrate  (ammonium is NH4+)

9.Aluminum sulfate + calcium phosphate 

10.Barium carbonate + hydrochloric acid 

11.Silver (I) acetate + potassium chromate 

12.Ammonium phosphate + barium hydroxide 

Section #5: Reactions in Aqueous Solutions

(Section 10.3, p. 292-299)

Read Section 10.3 and answer the following questions:

1. What is an aqueous solution?

2. In salt water, which is the solvent? Salt or Water?

3. In salt water, which is the solute? Salt or Water?

4. T or F: A precipitate is when a metal and a non-metal ion come together to form an insoluble (not soluble in water) product.

5. What is a spectator ion?

6. Which of the following is included in a Complete Ionic Equation:

a. Precipitate ions b. Spectator Ions c. Both

7. Which of the following is included in a NET Ionic Equation:

a. Precipitate ions b. Spectator Ions c. Both

8. Why are spectator ions NOT included in the net ionic equation (oops, did I just give away the answer to #7?) Write your response here:

Turn to Page 920 (yes, 920, go ahead, I'll wait here while you turn to that page…).

9. Which letter on Table C-10 Solubility Guidelines indicates a precipitate

a. S b. I

10. Which letter on Table C-10 Solubility Guidelines indicates a set of spectator ions?

a. S b. I

12. Look at the rules on p. 920 and circle the Precipitates in the list of a-h below. Some are precipitates, and some remain as spectator ions.

a. Sodium Chloride

b. Aluminum Acetate

c. Sodium Fluoride

d. Sodium Bromide

e. Mercury (I) Chloride

f. Strontium Sulfate

g. Sodium Carbonate

h. Magnesium Carbonate

ON THE TEST, I WILL GIVE YOU ONLY THE RULES #1-5, not the large grid below the rules. Be sure you know how to apply the rules!

Now turn back to p. 292

13. There are three types of double replacement reactions listed in section 10.3. The first one is Reactions that Form Precipitates. What do the other two form?

PRACTICE PROBLEMS p. 294-299SHOW ONLY THE SKELETAL and NET IONIC EQUATIONS for each one

Do practice problems 33, 36, 38, 39, 44