AP Statistics
Linear Transformations
El DoradoCommunity College considers a student to be full-time if he or she is taking between 12 and 18 units. The number of units X that a randomly selected El DoradoCommunity College full-time student is taking in the fall semester has the following distribution.
Number of Units (X) / 12 / 13 / 14 / 15 / 16 / 17 / 18Probability / 0.25 / 0.10 / 0.05 / 0.30 / 0.10 / 0.05 / 0.15
- At El Dorado Community College, the tuition for full-time students is $50 per unit. Let T = cost of tuition for the students. What is the expected cost and standard deviation for full-time students?
Cost of tuition (T)
Probability / 0.25 / 0.10 / 0.05 / 0.30 / 0.10 / 0.05 / 0.15
Notice:
- ______
- ______
- In addition to tuition charges, each full-time student at El Dorado Community College is assessed student fees of $100 per semester. If C = overall cost for a randomly selected full-time student, C = 100 + T.
Cost of tuition + fee (C)
Probability / 0.25 / 0.10 / 0.05 / 0.30 / 0.10 / 0.05 / 0.15
Notice:
- ______
- ______
- If a is being added to each value of X, what happens to µx ?
- If b is being multiplied with each value of X, what happens to µx ?
General statement about mean: ______
- If a is being added to each value of X, what happens to σx ?
- If b is being multiplied with each value of X, what happens to σx ?
General statement about standard deviation: ______
Example.
- Mrs. Prill’s AP Stat students have asked her to “curve” the grades on the last test. The tests had µx = 75 and σx =6.22.Jake requested that each grade be multiplied by 1.1 in order to get a 10% increase on each test grade. What would the new expected score and standard deviation be if Mrs. Prill were to agree to his proposal?
- In addition tothe 10% increase, Alex proposed that Mrs. Prill also add 5 points to each test. What would the new expected score and standard deviation be if Mrs. Prill were to agree to both proposals?
Tuition Charge (T) / 600 / 650 / 700 / 750 / 800 / 850 / 900
Probability / 0.25 / 0.10 / 0.05 / 0.30 / 0.10 / 0.05 / 0.15
The mean and standard deviation of this distribution are:
Notice that
- the shapes of both distributions are the same
- the mean of the distribution of T is 50 times bigger than the mean of X: 732.5 = 50(14.65)
- the standard deviation of T is 50 times bigger than the standard deviation of X: 103 = 50(2.06)
- Here is the probability distribution for C:
Overall Cost (C) / 700 / 750 / 800 / 850 / 900 / 950 / 1000
Probability / 0.25 / 0.10 / 0.05 / 0.30 / 0.10 / 0.05 / 0.15
The mean and standard deviation of this distribution are:
Notice that
- the shapes of both distributions are the same
- the mean of the distribution of C is $100 larger than the mean of T: 832.5 = 100 + 732.5
- the standard deviation of C is the same as the standard deviation of T
- We can add/subtract/multiply/divide to means.
- So then σy = |b|σx (you can only multiply/divide to standard deviations)