Name: ______ANSWER KEY______Date: ______Period: ______
Moles, Moles and More Moles – Unit 4 Quiz Review
Comparing atomic mass to molar mass
- The molar mass is the mass of 6.02 x 1023 atoms.
- Numerically the atomic mass and the molar mass are [the same, different] (circle one)
- For example the atomic mass of sodium is 22.99 AND the molar mass of sodium is 22.99.
- Both numbers come from the periodic table.
- Quantitatively the atomic mass and the molar mass are[the same, different] (circle one)
- For example the atomic mass is the mass of 1 atom and has units of amu.
- The molar mass is the mass of 6.02 x 1023atoms and has units of g/mol.
Molar Mass Practice Problems – REMEMBER this is addition…sig figs are to place value!!!
Determine the molar mass of the following using your periodic table. Remember, the units are g/mol.
1. Li2. Ca3. Al4. Cl25. O2
6.94g/mol40.08g/mol26.98g/mol70.90g/mol32.00g/mol
6. KCl7. MgI28. CCl49. Al2O310. SiO2
74.55g/mol278.11g/mol153.81g/mol101.96g/mol60.09g/mol
11. H212. CO213. Na2CO314. H2O15. NH3
2.02 g/mol44.01 g/mol57.99 g/mol18.02 g/mol17.04 g/mol
16. Cu17. Ne18. Phosphorus19. C6H12O6
63.55 g/mol20.18 g/mol30.97 g/mol180.18 g/mol
Chemical Quantities - CONVERTING BETWEEN MASS, MOLES AND PARTICLES
- When converting from grams to moles OR from moles to grams you use the molar massof the element or compound. You can tell because the conversion factor has units of g/mol.
- When converting from moles to molecules OR molecules to moles you use Avogadro’s number which is equal to 6.02 x 1023. You can tell because the conversion factor has units of particles/mole.
- When converting from atoms to moleculesORmolecules to atoms you use the chemical formula which tells how many atoms are in one molecule.
20. Calculate the # of atoms in 25g Ni - 2.6 x 1023 Ni atoms
- How many moles is 4.54 x 1022 molecules of H2O?.0754 moles H2O
- How many grams are in 2.8 mol of H2?5.6 g H2
- How many molecules of NH3 are in 5.0 moles of NH3? 3.0 x 1024NH3 molecules
- What is the number of moles in 125g of sodium carbonate (Na2CO3)?1.18 mol Na2CO3
- How many moles of copper is 127.1 g of copper?2.000 moles Cu
- How many atoms of phosphorous are there in 90.0 g of phosphorous?1.75 x 1024P atoms
- What is the mass of 1.74 x 1024 Ne atoms? 58.3 g Ne
- How many atoms are there is 36g glucose ( C6H12O6)?2.9 x 1024 atoms
- How many O atoms are in 12g of CO2? 3.3 x 1023 O atoms
% Composition & Empirical Formulas
Show all work, units, and round correctly.
- Determine the empirical formula for a compound containing: 63.50% Ag, 8.25% N, and 28.25% O.
63.5 % Ag 63.5 g Ag x 1 mol = 0.5887 mol = 1
107.87 g 0.5887
8.25 % N 8.25 g N x 1 mol = 0.589 mol = 1
14.007 g 0.5887
28.25 % O 28.25 g O x 1 mol = 1.766 mol = 3
16 0.5887
AgNO3
- Determine the percent composition of each element in a chemical sample that contains: 21.49 g Na, 56.15 g C, 9.43 g H, 74.81 g O, and 13.11 g N.
% Na = 21.49 g Na x 100 = 12.28 % Na% O = 74.81 g O x 100 = 42.75% O
174.99 g total 174.99 g total
% C = 56.15 g C x 100 = 32.09 % C% N = 13.11 g N x 100 = 7.492 % N
174.99 g total 174.99 g total
% H = 9.43 g H x 100 = 5.39 % H
174.99 g total
- Determine the empirical formula for the compound in the previous question.
12.28 g Na x 1 mol = 0.5341 mol = 1
22.99 g 0.5341
32.09 g C x 1 mol = 2.672 mol = 5
12.011 g 0.5341
5.39 g H x 1 mol = 5.34 mol = 10
1.008 g 0.5341
42.75 g O x 1 mol = 2.672 mol = 5
16 g 0.5341
7.492 g N x 1 mol = 0.5348 mol = 1
14.007 g 0.5341
NaC5H10O5N