INDIAN LEARNERS OWN ACADEMY, KUWAIT
CLASS / ASSIGNMENT BY / SYBJECT / LESSON/TOPICXII / Mr. BINU MATHEW / CHEMISTRY / SOLUTIONS
Answer the following
- Define the following(1) Molarity (2) Mole fraction
- A solution of glucose in water is labelled as 10% by weight. what would be the Molality of the Solution( Molar mass= 180)
- State Raoult’s law of solution containing Volatile component. How does Raoult’s law become a special case of Henry's law
- What type of deviation is shown by a mixture of ethanol and acetone? give reason
- Define the following (1) ideal solution (2) Azeotrope
- Why does a solution containing non-volatile solute have higher boiling point than pure solvent? Why is the elevation of boiling point a colligative property?
- 18g of glucose (molar mass= 180) is dissolved in 1kg of water in a pan. At what temperature will this solution boil (Kb for water= 0.512 Kkgmol-1 Boiling point of water
= 373.15K]
- l g of non-electrolyte solute is dissolved in 50g of benzene lowered the freezing point of benzene by 0.40 K.Find The molar mass of the solute ( Kf of benzene= 5. 12 Kkgmol-1
- Define molal elevations constant (Kb)
- Determine the osmotic pressure of a solution prepared by dissolving 2.5 ×10-2 g of K2SO4 in 2L of water at 25°C assuming that it is completely disassociated ( R=0.0821 L atm K-l mol-1 , Molar mass of K2SO4 =174 gmol-1
- Which Colligative property is used to determine the molar mass of bio molecule
- 3·9 g benzoic acid dissolved in 49 g of benzene shows a depression in freezing point of 1·62K.Calculate the van’t Hofffactor and predict the nature of solute (associated/dissociated).[Given : Molar mass ofBenzoic Acid = 122 g mol–1, Kf (H2O) = 1·86 K kg mol–1]
- 30 g of urea (M = 60 g mol-1) is dissolved in 846 g of water. Calculate the vapour pressure of water for this solution if vapour pressure of pure water at 298 K is 23.8 mm Hg.
- A 10% solution (by mass) of sucrose in water has a freezing point of 269·15 K. Calculate the freezing point of 10% glucose in water if the freezing point of pure water is 273·15 K.
(Molar mass of sucrose = 342 g mol-1) (Molar mass of glucose = 180 g mol-1)
- A solution of glucose (Molar mass = 180 g mol–1) in water has a boiling point of 100·20 0C. Calculate the freezing point of the same solution. Molal constants for water Kf and Kb are 1·86 K kg mol–1 and 0·512 K kg mol–1 respectively
LAST DATE OF SUBMISSION- 31/03/2018