14 Trigonometric Ratios

14 Trigonometric Ratios

Activity

Activity 14.1 (p. 14.4)

4. The two ratios are the same and it is a constant.

Quick Practice

Quick Practice 14.1 (p. 14.5)

(a)

(b)

Quick Practice 14.2 (p. 14.6)

(a) (cor. to 3 sig. fig.)

(b) (cor. to 3 sig. fig.)

Quick Practice 14.3 (p. 14.7)

(a) (cor. to 3 sig. fig.)

(b) ∵

Quick Practice 14.4 (p. 14.8)

(a)

(b)

(c)

Quick Practice 14.5 (p. 14.9)


Quick Practice 14.6 (p. 14.9)

Quick Practice 14.7 (p. 14.10)

Quick Practice 14.8 (p. 14.14)

(a)

(b)

Quick Practice 14.9 (p. 14.15)

(a) (cor. to 3 d.p.)

(b) (cor. to 3 d.p.)

(c) (cor. to 3 d.p.)

Quick Practice 14.10 (p. 14.16)

(a)

(b)

(c)


Quick Practice 14.11 (p. 14.17)

Quick Practice 14.12 (p. 14.18)

Quick Practice 14.13 (p. 14.18)

Quick Practice 14.14 (p. 14.22)

(a)

(b)

Quick Practice 14.15 (p. 14.23)

(a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

Quick Practice 14.16 (p. 14.24)

1.

2.

3.


Quick Practice 14.17 (p. 14.24)

Quick Practice 14.18 (p. 14.25)

Quick Practice 14.19 (p. 14.25)

Alternative solution

Quick Practice 14.20 (p. 14.29)

In △ABD,

In △ACD,


Quick Practice 14.21 (p. 14.30)

Draw AE ⊥ CD as shown in the figure.

AE = BC = 8 cm

CE = BA = 6 cm

In △AED,

Quick Practice 14.22 (p. 14.31)

Consider △OAC.

Area of the shaded region

Quick Practice 14.23 (p. 14.32)

In △ABE,

In △BCD,

∴ Length of the strip of metal


Quick Practice 14.24 (p. 14.37)

(a) Construct line segment OA such that OA makes an angle 10° with the positive x-axis.

(b) Construct line segment OB such that OB makes an angle 40° with the positive x-axis.

(c) Construct line segment OC such that OC makes an angle 55° with the positive x-axis.

(d) Construct line segment OD such that OD makes an angle 80° with the positive x-axis.

Further Practice

Further Practice (p. 14.10)

1. ∵

2. ∵


3. ∵

4.

Further Practice (p. 14.18)

1. ∵

2. ∵

3. ∵

Further Practice (p. 14.26)

1. ∵

2. ∵


3. ∵

Further Practice (p. 14.33)

1. In △ABC,

In △ABD,

2. Draw AE ⊥ BC as shown in the figure.

AE = DC = 10 cm

EC = AD = 4 cm

In △ABE,

3. Draw AE ⊥ CD as shown in the figure.

ED = AB = 60 m

AE = BD = 20 m

In △AEC,


Exercise

Exercise 14A (p. 14.11)

Level 1

1. (a)

(b)

(c)

(d)

2. (a)

(b)


3. (a)

(b) (Pyth. theorem)

4. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

(d) (cor. to 4 sig. fig.)

(e) (cor. to 4 sig. fig.)

(f) (cor. to 4 sig. fig.)

5. (a)

(b)

(c)


(d)

(e)

(f)

6. (a)

(b)

(c)

7. (a)

(b)

(c)

8. (a)

(b)

(c)

9. (a)

(b)

(c)

Level 2

10. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

11. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

12. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

13. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

14. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

15. (a) (cor. to 3 sig. fig.)

(b) ∵

16. (a)

(b)

(c)

(d)

17. (a)

(b)

18. (a)

(b)

19. (a) In △ABD,

In △ADC,

(b) In △QSR,

In △PQR,


20. (a) In △LMN,

In △MNK,

(b) In △BCD,

In △ABD,

Exercise 14B (p. 14.19)

Level 1

1. (a)

(b)

(c)

(d)

2. (a)

(b)

3. (a)

(b)

4. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

(d) (cor. to 4 sig. fig.)

(e) (cor. to 4 sig. fig.)

(f) (cor. to 4 sig. fig.)

5. (a)

(b)

(c)

(d)

(e)

(f)

6. (a)

(b)

(c)

7. (a)

(b)

(c)

8. (a)

(b)

(c)

Level 2

9. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

10. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

11. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

12. (a)

(b)

(c)

13. (a)

(b)

(c)

(d)

14. (a)

(b)

(c)

15. (a)

(b) ∵

16. (a)

(b) ∵

17. (a) In △BCD,

In △ABD,

(b) In △PRS,

In △PQS,

18. (a) In △MNK,

In △LMK,

(b) In △ABD,

In △BCD,


Exercise 14C (p. 14.26)

Level 1

1. (a)

(b)

(c)

2. (a)

(b)

(c)

3. (a) With the notations in the figure,


(b) With the notations in the figure,

(c) With the notations in the figure,

4. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

5. (a)

(b)

(c)

(d)

(e)

(f)

6. (a)

(b)

(c)

7. (a)

(b)

(c)

8. (a)

(b)

(c)

Level 2

9. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

10. (a) (cor. to 4 sig. fig.)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

11. (a)

(b) (cor. to 4 sig. fig.)

(c) (cor. to 4 sig. fig.)

12. (a)

(b)

(c)

13. (a)

(b)

(c)

14. (a)

(b)

15. (a) In △ABD,


In △ADC,

(b) In △PSR,

In △PQR,

16. (a) In △ABD,

In △BCD,

(b) In △QRS,

In △PQR,

17. (a) According to the question, AC is the longest side.

∴ △ABC is a right-angled triangle, where ÐB is a right angle. (Converse of Pyth. theorem)

(b) ∵

Exercise 14D (p. 14.33)

Level 1

1.

2.

3.

4. In △ABC,

In △ABD,

5.  In △PSQ,


In △PRQ,

6. In △ABC,

In △ACD,

7. In △PQR,

In △PRS,

8. In △BAD,

In △ABC,


9. In △PQR,

In △PRS,

10. (a) In △ABD,

(b) In △ABD,

In △ADC,

11. In △PQR,

In △PRS,


∴ Area of quadrilateral PQRS

12. Draw EI ⊥ FG as shown in the figure.

∵ IG = EH = 7 cm

∴ FI = FG – IG = (14 – 7) cm = 7 cm

In △EFI,

∴ HG = EI = 7 tan 55° cm

∴ Perimeter of trapezium EFGH

13.  (a) In △AOC,

(b) Area of sector OAB

Level 2

14.  (a)

In △OCD,

(b) In △OCD,


Area of the shaded region

15.

16. (a)

(b) With the notations in the figure,

In △,

∴ The height of the balloon above the ground is
95 m.

17. BG = EF = 10 m

In △AGB,


In △CED,

∴ Total length of the slide

18. (a) Let l m be the distance between the horizontal ground and the top of the ladder.

∴ The distance between the horizontal ground and the top of the ladder is 4.70 m.

(b)

19.  (a) In △BCD,

∴ ÐECF = ÐBCD = 40°

In △ECF,

(b) In △ABE,

(c) In △BCD,

(d) In △ABE,

∵ ∠ECF = ∠EFC = 40°

∴ EF = EC (sides opp. equal Ðs)

Revision Exercise 14 (p. 14.41)

Level 1

1. (a) (cor. to 3 sig. fig.)

(b) (cor. to 3 sig. fig.)

(c) (cor. to 3 sig. fig.)

(d) (cor. to 3 sig. fig.)

2. (a)

(b)

(c)

(d)

3. (a)

(b)

(c)

(d)

4.

5.

6.

7. ∵


8. ∵

9. ∵

10. ∵

11. ∵

12. ∵

13. ∵

14. ∵

15. ∵

16. ∵

17. ∵

18. (a) In △PQR,

(b) In △PQR,

(c) In △PRS,

(d)


19. In △ABD,

In △BCD,

20. In △LMN,

In △LNK,

21. In △EFH,

In △EFG,

22.  In △QRS,


In △PQS,

23. In △AOC,

∴ OB = OA = 5 cm

Area of the shaded region

24. In △CFE,

In △DEF,

The length of the tunnel


Level 2

25. Draw AE ^ BC as shown in the figure.

In △ABE,

Area of parallelogram ABCD

26. Draw PT ^ QR as shown in the figure.

In △PQT,

Area of trapezium PQRS

27.  Draw WQ and XR such that WQ⊥YZ and XR⊥WQ.

∴ RX // QY (int. ∠s supp.)


In △WXR,

In △WQZ,

28. (a) ∵ CFED is a square.

∴ DC = ED = x cm

∵ BD : DC = 5: 6

(b) In △BDE,

29. Draw DF ^ OA and join OD as shown in the figure.

In △COD,

∴ OF = 3 cm

In △DOF,

Area of the shaded region

30. (a) In △BCD,

∴ The angle that the pencil makes with BC is 59.0°.

(b) Draw EF⊥BF as shown in the figure.

In △BFE,

∴ The vertical distance from the top E of the pencil to the table is 13.7 cm.

31.  (a) In △ADC,

∴ The distance between C and D is 12.9 m.

(b) In △ADC,

In △BCD,

∴ The distance between B and C is 13.7 m.

32. In △ACK,

In △BCK,

33. Draw BC⊥AP as shown in the figure.

In △ACB,

In △BCP,

∴ The distance between ship P and lighthouse B is 1891 m.

34. With the notations in the figure,

in △ACD,

∵ CB = AD = L cm

∴ CD + DB = CB

35. ∵

∴ ST // PR (int. ∠s supp.)

In △PQR,

Challenging Questions (p. 14.45)

1. Draw AF ^ BC as shown in the figure.

∵ ABC is an equilateral triangle.

∴ ∠ABC = 60° (prop. of equil. △)

In △ABF,

Area of △ABC

Area of △BCD

Difference between the areas of △BDE and △ACE


2. ∵ AD = CD

∴ ∠CAD =∠ACD (base ∠s, isos. △)

Let AB = x.

In △ABD,

∵ CD = AD = 2x

In △ABC,

135