CHAPTER 6: CHEMICAL KINETICS – RATES OF REACTION

Key Ideas: p 358

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Introduction, p 358 : examples of chemical reactions, and where the rate of reaction is important.

6.1: Rate of Reaction:

Chemical kinetics : ______

-includes rates of reaction – times for reactions and concentration changes

-also includes models / theories to explain observations

-starting materials expensive – faster rate of reaction and more efficient reactions = more profits and cheaper medications

Describing Reaction Rates:

reaction rate = change of concentration per unit of time = c / t = mol / L / s = mol / L.s

-p 361 practice # 1,2.

-Graph of rate of consumption of a reactant – see p 362

-Graph of rate of production of a product – see p 363

-instantaneous rate of reaction = slope of tangent to line

-as concentration of reactant decreases, rate slows down

-rate may be based of decreasing concentration of reactant or increasing concentration of product – numbers of moles based on balanced chemical equations!

p 364 practice # 1, 2, 4.

Measuring Reaction Rates:

  1. Produce a gas: measure the volume of gas
  2. Involve ions: measure decreased ( reactant) or increased (product) conductivity of the solution
  3. Colour change – spectrophotometer used to measure changes in colour intensity

ex: ClO-1 (aq) + I-1 (aq)  IO-1 (aq) + Cl-1 (aq)

colourless colourless yellow colourless

ex: H2 (g) + I2 (g)  2 HI (g)

colourless purple colourless

p 365 practice # 5, 6, 7, 8, 9.

p 366 practice # 1, 2, 3ab

6.2: Factors Affecting the Rate of Reaction

  1. Chemical nature of the reactants:

-group 1 metals react faster with oxygen in the air than gold

-the farther down the group, the faster the reaction with air

-corrosion: many metals react with water / air to oxidize – or with acids

-ions react faster than molecules ex: glucose molecules or iron III ions with permanganate ions

  1. Concentration:

-the greater the concentration, the faster the reaction rate

  1. Temperature:

-usually the higher the temperature, the faster the reaction ex: cooking, reptile metabolism

  1. Presence of a Catalyst:

-catalyst: - speeds up reaction

-same amount of substance at the end as in the beginning, whether or not it is a reactant or not

-works by providing an alternative pathway with a lower activation energy

-so at a lower temp, more molecules have enough energy to overcome energy barrier

-so reaction happens faster

-ex: transition metals and their oxides – see table p 370

Homogeneous catalysts: reagents and catalyst in same phase: all gases, or all liquids

-NO2 is used as a catalyst in the production of SO3, to make sulfuric acid

Heterogeneous catalysts: catalysis happens at the point between two phases

-ex: MnO2 to catalyze the decomposition of hydrogen peroxide

Inhibitors: slow reactions down, by occupying active sites on catalyst or on the reactant

-can be used with catalyst to carefully control the rate of reaction

Catalytic Converters and Engine Exhaust

-transition metal oxides act as heterogeneous catalysts to reduce / remove unwanted products of incomplete combustion:

-products of combustion of gasoline include CO2, H2O and unburned hydrocarbons, CO and NO from the reaction of N2 and O2 in the hot engine.

-NO promptly reacts with O2 once out of the exhaust pipe to form NO2 – contributes to acid rain and the formation of smog and causes respiratory problems for all air-breathing organisms

-2 NO  N2 + O2 so less acid pollution is emitted

-hydrocarbons + CO + x O2  CO2 + H2O + Heat ( converter gets hot!!)

Catalysis in Industry:

-vital for savings in energy costs – reaction can happen at a lower temperature

-ex: series of reactions to get Zn from ZnS:

- ZnS (s) + H2SO4 + ½ O2  ZnSO4 + S (s) + H2O (l) too slow!!!!

Fortunately, FeS is also in Zn ore naturally, and the FeS reacts the same way, but more quickly.

FeS (s) + H2 SO4 + ½ O2  FeSO4 + S (s) + H2O (l)

Then the FeSO4 acts like a catalyst by taking part in the next reaction, and being regenerated in the

last reaction.

2 FeSO4 (aq) + H2SO4 + ½ O2  Fe2(SO4)3 (aq) + H2O (l)

Fe2(SO4)3 (aq) + ZnS (s)  ZnSO4 (aq) + 2 FeSO4 (aq) + S (s)

-N.B. – catalysts may take part in the reaction, but are regenerated in the process so at the end the catalyst still exists- like iron II sulfate above

-specific catalyst needed for a specific reaction

-choice of catalysts used to be a trial and error process, involving transition metals and their compounds usually

-with knowledge to the structure of the reaction and the catalysis, a more efficient process of choosing a catalyst should soon be a reality.

Enzymes: natural catalysts in living organisms

-life wouldn’t be able to exist without them!

-ex: lactase to digest lactose ( milk sugar )

  1. Surface Area:

-the more finely divided the surface, the greater the contact between reactant molecules and the faster the reaction

-ex: burning a block of wood vs burning wood shavings vs burning saw dust

-especially for heterogeneous systems – G with S, L with S, G with L

p 371 practice: 1, 2, 3, 4, 5.

section 6.2 practice: # 1.

6.3: Rate Laws and Order of Reaction

Empirical Determination of Rate Laws

-rate law: ______

-need to be determined for any specific reaction by experimental evidence

-if a A + b B  products, then rate  [A]m [B]n or rate = k [A]m [B]n

-both m and n and K have to be determined from experimental evidence

-the exponents and k may be any real number and differ for each reaction

Order: if exponent is 1, we say the reaction is a first order reaction with respect to that reactant

-if exponent is 2, then second order reaction with respect to that reactant, etc.

Overall reaction order: determined by the sum of the exponents: m + n

Determining Exponents of the Rate Law:

-examine experimental data – change in concentration per second measured under identical conditions – the only factor changed for each trial is the concentration of one reactant

-while conc of one reactant remains the same how does rate change with the change in conc of the other reactant?

-if conc doubles and rate doubles, then exponent is 1 : 21 = 2

-if conc doubles and rate is 4 times faster, then exponent is 2: 22 = 4

-see examples p 375-376