1) a Store Sells Hats for $12 and Ties for $22

Name Easter 2007 Review

Alg1DO IN NBDue: Monday, 4/16/07

Part I:
Let/Solve/Check
1) A store sells hats for $12 and ties for $22. Last weekend the store sold 7 fewer ties than double the amount of hats and the sales were $2,926. How many of each were sold?

2) A store sells hats for $12 and ties for $22. 160 total items were sold and total sales were $2,430. How many of each were sold?

3) A phone call cost $5.19. Introductory minutes cost $.21/min and additional minutes are $.13/min. If there were 3 more additional minutes than triple the introductory minutes, how many minutes were billed at each rate?

4) A 31-minute phone call cost $5.07. Introductory minutes cost $.21/min and additional minutes are $.13/min. How many minutes were billed at each rate?

5) Find 5 consecutive integers with the sum of -905.

6) Find 4 consecutive even integers such that the sum of the 2nd and 4th is 176.

7)Find 6 consecutive odd integers such that the sum of the 4thand the 6th is 139 lessthan 5 times the 3rd.

Solve Algebraically and Check:
8) 5x + 7y =-2 9) 9x + 4y = -36 10) 8x - 5y =111) 11x +4y =19
11x - 8y = 136 -7x + 15y = 28 6x - 11y =-79 -7x + 9y =138

Solve and Graph:
12) 2 | 12x – 4 | - 11 . -1113)3| 8x – 4 | + 14 23
- 7 12

Multiply:
14) (3x + 8)(2x – 7)15) (3x – 4)216) (5x + 6)3

17) (5x – 2)(4x2 + 2x – 5)18) (3x2 + 7x + 2)(8x2 -5x + 4)

Part II:
Solve each equation:(linear and quadratic together... round to the hundredth if necessary.)
1) 20 - (5/8)x = 402) 6(7x - 2) = 8(4x + 1) 3) 2(5x - 4) - 3(4x + 3) = -43
4) x2+ 44 = 15x5) 3x2+ 18x = 81 6) 3x2 = 5x + 5
7) 11x - 5 = 7x - 538) 6(3x + 1) + 5(10 - 4x)= 39 9) ¼x - 33 = -49
10) 7x2 - 1 = 3x11) 9(3x + 1) = 8(5x + 6) 12) 15x = x2– 16
13) x2 + 8x = 1214) 9(4x + 7) - 6(7x + 10) = -54 15) 44 = 20 - 2x
16) 4x2 - 128 = 16x17) 3x2 - 8x + 6 = x + 6 18) 7(6x + 2) = 10(3x + 5)
19) 3x2 + 13x - 12 = 9x2 - 11x - 12 20) 2x2 - 14 = 10x

Part III:
Parallel/Perpendicular: (Graph all 3 lines for each question)

a) Use the two points to find the equation of the line.

b)For the line found in part a, find a line that is parallel and passes through the given point.

c)Find the equation of a line that is perpendicular and passes through the given point.

Given Line:Parallel:Perpendicular:

1) (-5, 13) (3, -11)(4,-9)(3,6)

2) (-6,0) (-6,5)(4,3) (6,-7)

3) (2,6)(2,-19)(5,14)(5,-8)

4) (-4,2) (8,5)(-4, 10)(-6,-8)

Solve Each System Graphically and check:

5) y + 1 = -3(x – 2)6) y + 4 = - ¾ (x – 8)

11x – 11y = 77 y = 8

Graph each inequality

7) y + 6 > - ¼ (x – 12)8) 36x – 12y > 12

y < -5

9) x 410) y – 4 -2(x + 1)
13x – 52y > 52