Math 121 Review for Exam 2
1. Truncate to 4 significant digits.
(a) 0.0040549 (b) 870723 (c) 70.005 (d) 83066
2. Round to 3 siginificant digits.
(a) 0.0070378 (b) 960645 (c) 0.0999607 (d) 98.747
3. Find the indicated absolute values.
(a) (b) (c) (d)
4. Rewrite each number without an exponent
(a) (b) (c) 728.2 E +2 (d)
5. Rewrite each decimal number in decimal normalized exponential form.
(a) 0.000706 (b) 910000 (c) (d)
6. Rewrite each decimal number in scientific notation.
(a) 4090000 (b) 0.0000083 (c) (d)
7. Rewrite each binary number in binary normalized exponential form.
(a) 0.00001011 (b) 100101000 (c) (d)
8. Rewrite each binary number in binary scientific notation..
(a) 0.00011011 (b) 10110100 (c) (d)
9. Write
(a) as a 32-bit binary integer.
(b) as a 32-bit binary floating point number using the current IEEE standard.
Hint: bit 0: sign
bits 1 to 8: 127 more than the binary scientific notation exponent
bits 9 to 31: the fractional part of the binary scientific notation mantissa
(c) in ASCII binary code Hint: 7 = 0011_0111 and 3 = 0011_0011 in ASCII.
10. Compute and write the answer as
(a) an integer quotient and remainder. (b) a mixed number.
(c) a repeating decimal. (d) a truncated decimal with 3 significant digits.
(e) a rounded decimal with 3 significant digits.
11. Compute and write the answer in decimal normalized exponential form.
(a) (b)
(c) (d)
12. Compute and write the answer in scientific notation.
(a) (b)
(b) (d)
Math 121 Answers to Review for Exam 2
1.(a) 0.004054 (b) 870700 (c) 70.00 (d) 83060
2.(a) 0.00704 (b) 961000 (c) 0.1000 (d) 98.7
3.(a) 5 (b) 37 (c) 13 (d) 2
4.(a) 0.000058 (b) 482000000 (c) 72820 (d) 0.84
5.(a) (b) (c) (d)
6.(a) (b) (c) (d)
7.(a) (b) (c) (d)
8.(a) (b) (c) (d)
9.(a) 0000_0000_0000_0000_0000_0000_0100_1001
(b) 0 100_0010_1 001_0010_0000_0000_0000_0000
(c) 0011_0111_0011_0011
10.(a) 3 R 2 (b) (c) (d) 3.28 (e) 3.29
11.(a) (b) (c) (d)
12.(a) (b) (c) (d)