Fall 2012 Semester Exam

Four Questions of this type.

1.Evaluate 4v+6w for v=3 and w=–2.

4(3) + 6(-2) = 12 = 0

Two Questions of this type.

Simplify the expression.

5.

a. b.

c. d.

9a -9 + 4a – 4 = 13a - 13

Two Questions of this type.

Determine which value is a solution of the equation.

7.10x + 7 = 57

a.64 b.50 c.2 d.5

10x + 7 = 57

-7 = -7

10 x = 50

10 x = 50

10 10

x = 5

One Question of this type.

Solve the absolute value equation.

9.

a., b., c., d.,

5a + 3 = 5 or 5a + 3 = -5

-3 = -3 -3 = -3

5a = 2 5a = -8

5a = 2 5a = -8

5 5 5 5

a = 2/5 or a = -8/5

Three Questions of this type.

10.Find the range of the relation .

a. b.

c. d.

Four Questions of this type. Linear and Absolute Value graphs.

14.Graph the function – 4 for the domain –1. Classify the function as discrete or continuous. Then identify the range of the function.

a. /
discrete; range is
b. /
continuous;
c. /
continuous;
d. /
continuous; range is y -4.5

Three Questions of this type.

Graph the linear system and estimate the solution.

17.

a. / (1, –4)

b. / (–3, 2)

c. / (–1, –3)

d. / (3, 1)

Four Questions of this type.

Solve the linear system.

20.

Change the sign of top eq. 4x + 3y = 27

Leave 2nd Eq. as is -4x + 4y = 8

Add the 2 equations 0 + 7y = 35

7y = 35

7 7

Sub y into one of the eq. y = 5

-4x – 3(5) = -27

-4x – 15 = -27

+15 +15

-4x = -12

x = 3

a.(–5, –5) b.(–1, –5) c.(3, 5) d.no solution

22.Mr. Jarvis invests a total of $6,853 in two savings accounts. One account yields 7% simple interest and the other 6.5% simple interest. He would like to find the amount placed in each account if a total of $459.15 in interest is received after one year. Which system of linear equations below expresses this problem?

7% is .07 as a decimal

6.5% is .065 as a decimal

The total interest is $459.15

So choose b

a. / x + y = 459.15
7x + 6.5y = 6,853
b. / x + y = 6,853
0.07x + 0.065y = 459.15
c. / x + y = 459.15
0.07x + 0.065y = 6,853
d. / x + y = 6,853
7x + 6.5y = 459.15

Three Questions of this type.

Graph the system of inequalities.

24.use a test point like (0, -5)

a. b. c. d.

Three Questions of this type.

27. Which ordered triple is a solution of the system of equations?

multiply second eq. by 2, add to top eq.

16x – 8y + 4z = -2

-16x – 8y -16z = -16

0 -16y – 12z = -18

Multiply the second eq by -3 and 3rd by 2

Add the new 2nd and 3rd eq.

24x +12y +24z = 24

-24x – 8y -32z = -14

0 4y – 8z = 10

Put the 2 new equations in a system

-16y – 12z = -18 -16y – 12z = -18

4y – 8z = 10 mult by 4 16y – 32z = 40

-44z = 22

-44z = 22

-44 -44

z = -1/2

Sub z into one of the new eq.

4y – 8(-1/2) = 10

4y + 4 = 10

-4 -4

4y = 6

y = 6/4 = 3/2

a.(, , ) b.(, , ) c.(, , ) d.(, , )

Two Questions of this type.

30.If A = and B= , find

a. b. c. d.

Five Questions of this type.

32.Graph .

a. /
b. /
c. /
d. /

36. Graph the function. Label the vertex, axis of symmetry, and x-intercepts.

a. /
vertex: (, ) AOS: x = x-int: –4, –2
b. /
vertex: (, ) AOS: x = x-int: –4, –2
c. /
vertex: (, ) AOS: x = x-int: 2, 4
d. /
vertex: (, ) AOS: x = x-int: 2, 4

Three Questions of this type.

Factor the expression.

37.

a. b. c. d.

See Factoring Review for steps

Four Questions of this type.

Factor the expression.

40.

a. b. c. d.

See Factoring Review for steps

Two Questions of this type.

Factor completely.

44.

a. b. c. d.

See Factoring Review for steps

One Questions of this type.

Simplify the expression.

46.

a. b. c. d.

See Factoring Review for steps

Two Questions of this type.

Solve.

See Factoring Review for steps

48. = 59

-17 -17

3(x + 7)2 = 42

3(x + 7)2 = 42

3 3

(x + 7)2 = 14

x + 7 = ±

x = -7 ±

a. b. c. d.

Two Easy Questions that you should not get wrong