Chapter 18: Statistical Quality Control 1
Chapter 18
Statistical Quality Control
LEARNING OBJECTIVES
Chapter 18 presents basic concepts in quality control, with a particular emphasis on statistical quality control techniques, thereby enabling you to:
1.Understand the concepts of quality, quality control, and total quality management.
2.Understand the importance of statistical quality control in total quality management.
3.Learn about process analysis and some process analysis tools, including Pareto charts, fishbone diagrams, and control charts.
4.Learn how to construct charts, R charts, p charts, and c charts.
5.Understand the theory and application of acceptance sampling.
CHAPTER OUTLINE
18.1Introduction to Quality Control
What Is Quality Control?
Total Quality Management
Some Important Quality Concepts
Benchmarking
Just-in-Time Inventory Systems
Reengineering
Six Sigma
Team Building
18.2 Process Analysis
Flowcharts
Pareto Analysis
Cause-and-Effect (Fishbone) Diagrams
Control Charts
18.3Control Charts
Variation
Types of Control Charts
Chart
R Charts
p Charts
c Charts
Interpreting Control Charts
18.4Acceptance Sampling
Single Sample Plan
Double-Sample Plan
Multiple-Sample Plan
Determining Error and OC Curves
KEY TERMS
acceptance samplingPareto analysis
after-process quality controlPareto chart
benchmarkingprocess
c chartproducer’s risk
cause-and-effect diagramproduct quality
centerlinequality
consumer's riskquality circle
control chartquality control
double-sample planR chart
fishbone diagramreengineering
flowchartsingle-sample plan
in-process quality controlSix Sigma
Ishikawa diagramteam building
just-in-time inventory systemstotal quality management (TQM)
lower control limit (LCL)transcendent quality
manufacturing qualityupper control limit (UCL)
multiple-sample planuser quality
operating characteristic (OC) curvevalue quality
p chart chart
STUDY QUESTIONS
1.The collection of strategies, techniques, and actions taken by an organization to assure themselves that they are producing a quality product is ______.
2.Measuring product attributes at various intervals throughout the manufacturing process in an effort to pinpoint problem areas is referred to as ______quality control.
3.Inspecting the attributes of a finished product to determine whether the product is acceptable, is in need of rework, or is to be rejected and scrapped is ______quality control.
4.An inventory system in which no extra raw materials or parts are stored for production is called a ______system.
5.When a group of employees are organized as an entity to undertake management tasks and perform other functions such as organizing, developing, and overseeing projects, it is referred to as ______.
6.A ______is a small group of workers, usually from the same department or work area, and their supervisor, who meet regularly to consider quality issues.
7.The complete redesigning of a company's core business process is called ______. This usually involves innovation and is often a complete departure from the company's normal way of doing business.
8.A total quality management approach that measures the capability of a process to perform defect-free work is called ______.
9.A methodology in which a company attempts to develop and establish total quality management from product to process by examining and emulating the best practices and techniques used in their industry is called ______.
10.A graphical method for evaluating whether a process is or is not in a state of statistical control is called a ______.
11.A diagram that is shaped like a fish and displays potential causes of one problem is called a ______or ______diagram.
12.A bar chart that displays a quantitative tallying of the numbers and types of defects that occur with a product is called a ______.
13.Two types of control charts for measurements are the ______chart and the ______chart. Two types of control charts for attribute compliance are the ______chart and the ______chart.
14.An x bar chart is constructed by graphing the ______of a given measurement computed for a series of small samples on a product over a period of time.
15.An R chart plots the sample ______. The centerline of an R chart is equal to the value of ______.
16.A p chart graphs the proportion of sample items in ______for multiple samples. The centerline of a p chart is equal to ______.
17.A c chart displays the number of ______per item or unit.
18.Normally, an x bar chart is constructed from 20 to 30 samples. However, assume that an x bar chart can be constructed using the four samples of five items shown below:
Sample 1Sample 2 Sample 3 Sample 4
23 21 19 22
22 18 20 24
21 22 20 18
23 19 21 16
22 19 20 17
The value of A2 for this control chart is ______.
The centerline value is ______.
The value of is ______.
The value of UCL is ______.
The value of LCL is ______.
The following samples have means that fall outside the outer control limits ______. In constructing an R chart from these data, the value of the centerline is ______. The value of D3 is ______and the value of D4 is ______. The UCL of the R chart is ______and the value of LCL is ______.
The following samples have ranges that fall outside the outer control limits ______.
19.p charts should be constructed from data gathered from 20 to 30 samples. Suppose, however, that a p chart could be constructed from the data shown below:
Sample n Number out of Compliance
1 70 3
2 70 5
3 70 0
4 70 4
5 70 3
6 70 6
The value of the centerline is ______.
The UCL for this p chart is ______.
The LCL for this p chart is ______.
The samples with sample proportions falling outside the outer control limits are ______.
20.c charts should be constructed using at least 25 items or units. Suppose, however, that a c chart could be constructed from the data shown below:
Item Number of
Number Nonconformities
1 3
2 2
3 2
4 4
5 0
6 3
7 1
The value of the centerline for this c chart is ______.
The value of UCL is ______and the value of LCL is ______.
21.A process is considered to be out of control if ______or more consecutive points occur on one side of the centerline of the control chart.
22.Four possible causes of control chart abnormalities are (at least eight are mentioned in the text) ______, ______, ______, and ______.
23.Suppose a single sample acceptance sampling plan has a c value of 1, a sample size of 10, a p0 of .03, and a p1 of .12. If the supplier really is producing 3% defects, the probability of accepting the lot is ______and the probability of rejecting the lot is ______. Suppose, on the other hand, the supplier is producing 12% defects. The probability of accepting the lot is ______and the probability of rejecting the lot is ______.
24.The Type II error in acceptance sampling is sometimes referred to as the ______risk. The Type I error in acceptance sampling is sometimes referred to as the ______risk.
25.Using the data from question 22, the producer's risk is ______and the consumer's risk is ______. Assume that 3% defects is acceptable and 12% defects is not acceptable.
26.Suppose a two-stage acceptance sampling plan is undertaken with c1 = 2, r1 = 6, and c2 = 7. A sample is taken resulting in 4 rejects. A second sample is taken resulting in 2 rejects. The final decision is to ______the lot.
ANSWERS TO STUDY QUESTIONS
1. Quality Control16. Noncompliance, p (average
proportion)
2. In-Process
17. Nonconformances
3. After-Process
18. 0.577, 20.35, 4.0, 22.658, 18.042,
4. Just-in-Time None, 4.0, 0, 2.115, 8.46, 0.00, None
5. Team Building19. .05, .128, .000, None
6. Quality Circle20. 2.143, 6.535, 0.00
7. Reengineering21. 8
8. Six Sigma22. Changes in the Physical Environment,
Worker Fatigue, Worn Tools, Changes
9. Benchmarking in Operators or Machines,
Maintenance, Changes in Worker
10. Control Chart Skills, Changes in Materials, Process
Modification
11. Fishbone, Ishikawa
23. .9655, .0345, .6583, .3417
12. Pareto Chart
24. Consumer’s, Producer’s
13. , R, p, c
25. .0345, .6583
14. Means
26. Accept
15. Ranges,
SOLUTIONS TO ODD-NUMBERED PROBLEMS IN CHAPTER 18
18.5 = 4.55, = 4.10, = 4.80, = 4.70,
= 4.30, = 4.73, = 4.38
R1 = 1.3, R2 = 1.0, R3 = 1.3, R4 = 0.2, R5 = 1.1, R6 = 0.8, R7 = 0.6
= 4.51 = 0.90
For Chart: Since n = 4, A2 = 0.729
Centerline: = 4.51
UCL: + A2 = 4.51 + (0.729)(0.90) = 5.17
LCL: – A2 = 4.51 – (0.729)(0.90) = 3.85
For R Chart: Since n = 4, D3 = 0 D4 = 2.282
Centerline: = 0.90
UCL: D4 = (2.282)(0.90) = 2.05
LCL: D3 = 0
Chart:
R Chart:
18.7 = .025, = .000, = .025, = .075,
= .05, = .125, = .05
p = .050
Centerline: p = .050
UCL: .05 + 3 = .05 + .1034 = .1534
LCL: .05 – 3 = .05 – .1034 = .000
p Chart:
18.9 = = 1.34375
Centerline: = 1.34375
UCL: = 1.34375 + 3 =
1.34375 + 3.47761 = 4.82136
LCL: = 1.34375 – 3 =
1.34375 – 3.47761 = 0.000
c Chart:
18.11While there are no points outside the limits, the first chart exhibits some problems. The chart ends with 9 consecutive points below the centerline. Of these 9 consecutive points, there are at least 4 out of 5 in the outer 2/3 of the lower region. The second control chart contains no points outside the control limit. However, near the end, there are 8 consecutive points above the centerline. The p chart contains no points outside the upper control limit. Three times, the chart contains two out of three points in the outer third. However, this occurs in the lower third where the proportion of noncompliance items approaches zero and is probably not a problem to be concerned about. Overall, this seems to display a process that is in control. One concern might be the wide swings in the proportions at samples 15, 16 and 22 and 23.
18.13n = 10 c = 0 p0 = .05
P(x = 0) = 10C0(.05)0(.95)10 = .5987
1 – P(x = 0) = 1 – .5987 = .4013
The producer's risk is .4013
p1 = .14 P(x = 0) = 15C0(.14)0(.86)10 =.2213
The consumer's risk is .2213
18.15n = 8 c = 0 p0 = .03 p1 = .1
p Probability
.01 .9227
.02 .8506
.03 .7837
.04 .7214 Producer's Risk for (p0 = .03) =
.05 .6634 1 – .7837 = .2163
.06 .6096
.07 .5596
.08 .5132 Consumer's Risk for (p1 = .10) = .4305
.09 .4703
.10 .4305
.11 .3937
.12 .3596
.13 .3282
.14 .2992
.15 .2725
OC Chart:
18.17
Stop
N
(no)
D K L M (yes) Stop
Stop
(no) (no)
Start A B (yes) C E F G
(yes)
H(no) J Stop
(yes)
I
18.19Fishbone Diagram:
18.21 = .06, = .22, = .14, = .04, = .10,
= .16, = .00, = .18, = .02, = .12
p = = .104
Centerline: p = .104
UCL: .104 + 3 = .104 + .130 = .234
LCL: .104 – 3 = .104 – .130 = .000
p Chart:
18.23 n = 15, c = 0, p0 = .02, p1 = .10
p Probability
.01 .8601
.02.7386
.04 .5421
.06 .3953
.08 .2863
.10 .2059
.12 .1470
.14 .1041
Producer's Risk for (p0 = .02) = 1 – .7386 = .2614
Consumer's Risk for (p1 = .10) = .2059
OC Curve:
18.25 = 1.2100, = 1.2050, = 1.1900, = 1.1725,
= 1.2075, = 1.2025, = 1.1950, = 1.1950,
= 1.1850
R1 = .04, R2 = .02, R3 = .04, R4 = .04, R5 = .06, R6 = .02,
R7 = .07, R8 = .07, R9 = .06,
= 1.19583 = 0.04667
For Chart: Since n = 9, A2 = .337
Centerline: = 1.19583
UCL: + A2 = 1.19583 + .337(.04667) =
1.19583 + .01573 = 1.21156
LCL: – A2 = 1.19583 – .337(.04667) =
1.19583 – .01573 = 1.18010
For R Chart: Since n = 9, D3 = .184 D4 = 1.816
Centerline: = .04667
UCL: D4 = (1.816)(.04667) = .08475
LCL: D3 = (.184)(.04667) = .00859
Chart:
R chart:
18.27
= .12, = .04, = .00, = .02667,
= .09333, = .18667, = .14667, = .10667,
= .06667, = .05333, = .0000, = .09333
p = = .07778
Centerline: p = .07778
UCL: .07778 + 3 = .07778 + .09278 = .17056
LCL: .07778 – 3 = .07778 – .09278 = .00000
p Chart:
18.29 n = 10 c = 2 p0 = .10 p1 = .30
p Probability
.05 .9885
.10 .9298
.15 .8202
.20 .6778
.25 .5256
.30 .3828
.35 .2616
.40 .1673
.45 .0996
.50 .0547
Producer's Risk for (p0 = .10) = 1 – .9298 = .0702
Consumer's Risk for (p1 = .30) = .3828
18.31
= .05, = .00, = .15, = .075,
= .025, = .025, = .125, = .00,
= .10, = .075, = .05, = .05,
= .15, = .025, = .000
p = = .06
Centerline: p = .06
UCL: .06 + 3 = .06 + .11265 = .17265
LCL: .06 – 3 = .06 – .112658 = .00000
p Chart:
18.33There are some items to be concerned about with this chart. Only one sample range is above the upper control limit. However, near the beginning of the chart there are eight sample ranges in a row below the centerline. Later in the run, there are nine sample ranges in a row above the centerline. The quality manager or operator might want to determine if there is some systematic reason why there is a string of ranges below the centerline and, perhaps more importantly, why there are a string of ranges above the centerline.
18.35The centerline of the c chart indicates that the process is averaging 0.74 nonconformances per part. Twenty-five of the fifty sampled items have zero nonconformances. None of the samples exceed the upper control limit for nonconformances. However, the upper control limit is 3.321 nonconformances which, in and of itself, may be too many. Indeed, three of the fifty (6%) samples actually had three nonconformances. An additional six samples (12%) had two nonconformances. One matter of concern may be that there is a run of ten samples in which nine of the samples exceed the centerline (samples 12 through 21). The question raised by this phenomenon is whether or not there is a systematic flaw in the process that produces strings of nonconforming items.