Materials 3F03 Materials Production 2
Assignment 1: Design of Optimized route for copper smelting.
February 3 2016, Part 1(a,b,c and d)Due February 12th, Final Report March 16th 2016
.
You are being asked to design the optimum process for each of two concentrates which contain only FeS and Cu2S. Concentrate A contains 54% FeS and Concentrate B contains 25% FeS.
Your plant consists of an Inco Flash Smelter and Pierce Smith Converter. You are asked to maximize copper yield. You know from experience that the optimum slag will contain 35%SiO2.
Answers by February 12 for a, b, c and d (25%)
Form teams of 4 to discuss your ideas, one report to be returned by each team all members listed on submission
This part of the project is for all the team to share their ideas and form a clear picture of the problem. By sharing that picture with other teams an even clearer picture will be developed. In answering a, b, c and d you are expected to form a set of instructions for the solution to the problem. It should be possible to hand your answers to these questions to another group and for them to use them as instructions for the optimization.
a/ What must you consider in your design?
b/ Define the reactions involved in the process.
c/ Define the calculations that are required and stepwise plan for the calculations.
d/ What data do you need that is not supplied?
aFeO in slag.
Mid project progress discussion February 25th
Teams to split the calculation process evenly all members must contribute then come together and discuss the results.
e/ complete design calculations and determine optimum process for each concentrate
f/ discuss any unresolved issues and ways they might be addressed.
g/ prepare final report
Cp = A + B*10^-3T + C*10^5/T^2 cal/mole/K
Compound / Tmin / Tmax / s / A / B / C / Htrans / H0298 / MWCu / 298 / 1357 / m / 5.41 / 1.50 / 0.00 / 3120 / 0 / 63.54
Cu / 1357 / 2800 / b / 7.50 / 0.00 / 0.00 / 72800 / 0 / 63.54
Cu2S / 298 / 376 / T / 19.50 / 0.00 / 0.00 / 920 / -19600 / 159.15
Cu2S / 370 / 623 / T / 23.25 / 0.00 / 0.00 / 200 / -19600 / 159.15
Cu2S / 623 / 1400 / M / 20.32 / 0.00 / 0.00 / 2600 / -19600 / 159.15
Cu2S / 1400 / ? / 21.30 / 0.00 / 0.00
N2 / 298 / 2500 / 6.66 / 1.02 / 0.00 / 0 / 0 / 28.02
O2 / 298 / 3000 / 7.16 / 1.00 / -0.40 / 0 / 0 / 32.00
SO2 / 298 / 2200 / 11.04 / 1.88 / -1.84 / 0 / -70950 / 64.07
FeO / 298 / 1650 / M / 11.66 / 2.00 / -0.67 / 7490 / -63200 / 71.85
FeO / 1650 / 2200 / 16.30 / 0.00 / 0.00 / 0 / -63200 / 71.85
SiO2 / 298 / 848 / T / 11.22 / 8.20 / -2.70 / 290 / -2E+05 / 60.09
SiO2 / 848 / 2200 / M / 14.41 / 1.94 / 0.00 / 3600 / -2E+05 / 60.09
SiO2 / 2200 / 13.38 / 3.68 / -3.45 / 60.09
FeS / 298 / 411 / t / 0.12 / 40.00 / 0.00 / 570 / -24000 / 87.91
FeS / 411 / 598 / t / 17.40 / 0.00 / 0.00 / 120 / 87.91
FeS / 598 / 1468 / m / 12.20 / 2.38 / 0.00 / 7730 / 87.91
FeS / 1468 / 2000 / 17.00 / 0.00 / 0.00 / 87.91
These represent thermodynamic data for the formation of compounds from their constituent elements.
GO = / A + / B*T / Cal/mol.1) / Cu2O / -34980 + / 14.41 T
2) / Cu2S / -35160 + / 10.05 T
3) / SO2 / -86620 + / 17.31 T
4) / FeO / -54890 + / 10.55 T
5) / Fe304 / -260870 + / 72.24 T
6) / FeS / -24250 + / 5.50 T
Copper loses to the slag can be calculated by
(wt.% Cu) = 36(aCu2O)0.5