Solutions and Colligative Review

Name ______Date ______Period ______

Solutions and Colligative Review

Molarity Review

1.  How many grams of solute are necessary to make:

a) 250. ml of 0.0100 M Na2CrO4 c) 500. ml of 0.250 M NaBr

b) 100. ml of 0.050 M CoCl2 d) 100. ml of 0.50 M KCl

2.  How many mL of a 0.100 M solution contain:

a) 0.1 mole NaCl c) 0.05 mole Zn(NO3)2

b) 0.01 mole HCl d) 0.0750 mole NaI

3.  How many mL of a 0.2 M solution contain:

a) 8.40 g of NaHCO3 c) 1.17 g of NaCl

b) 5.95 g of KBr d) 1.01 g of KNO3

4.  What is the concentration of the following solutions:

a)  5.85 g NaCl dissolved in water to make 250 mL total volume.

b)  4.25 g NaNO3 dissolved in water to make 100 mL total volume.

c)  4.17 g KBr dissolved in water to make 500 mL total volume.

d)  1.90 g SnCl2 dissolved in water to make 1000 mL total volume.

Molality Review

1.  Calculate the molality when 75.0 grams of MgCl2 is dissolved in 500.0 g of solvent

2.  100.0 grams of sucrose (C12H22O11, mol. wt. = 342.3 g/mol) is dissolved in 1.50 L of water. What is the molality?

3.  49.8 grams of KI is dissolved in 1.00 kg of solvent. What is the molality

4.  Calculate the molality if 2.89 g of NaCl dissolved in 0.159 L of water (density of water is 1.00 g/mL)

5.  Calculate the molality if 1.80 mol KCl is dissolved in 16.0 mol of H2O

6.  Calculate the molality if 13.0 g benzene, C6H6 is dissolved in 17.0 g CCl4

Dilution Review

1.  If I add 25.0 mL of water to 125 mL of a 0.15 M NaOH solution, what will the molarity of the diluted solution be?

2.  If I add water to 100 mL of a 0.15 M NaOH solution until the final volume is 150 mL, what will the molarity of the diluted solution be?

3.  How much 0.05 M HCl solution can be made by diluting 250 mL of 10 M HCl?

4.  How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?

Boiling and Freezing Point Changes

1.  If I add 45 grams of sodium chloride to 500 grams of water, what are the new melting and boiling points of the resulting solution? Kb(H2O) = 0.52 0C/m and Kf(H2O) = 1.86 0C/m.

2.  Which solution will have a higher boiling point: A solution containing 105 grams of sucrose (C12H22O11) in 500 grams of water or a solution containing 35 grams of sodium chloride in 500 grams of water

Answers

Molarity

1) a. 0.405 g 2) a. 1000 mL 3) a. 500 mL 4) a. 0.40 M

b. 0.65 g b. 100 mL b. 300 mL b. 0.5 M

c. 12.9 g c. 500 mL c. 100 mL c. 0.07 M

d. 3.7 g d. 750. mL d. 50 mL d. 0.01 M

Molality

1) 1.58 m 2) 0.195 m 3) 0.300m 4) 0.311 m 5) 6.24 m 6) 9.79 m

Dilution

1) 0.75M 2) 0.100 M 3) 50,000mL 4) 700mL of water

Boiling and Freezing Point changes

1) Melting point = -5.730 C, boiling point = 101.600 C 2) sodium chloride solution has a

higher boiling point