Test/GT-2/Set-P Mittal Sir

Test/GT-2/Set-P Mittal Sir

Test/GT-2/Set-P Mittal Sir

III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.

email : , website :

GT-2

TEST-/12th & 12th Passed

Topic : ORGANIC CHEMISTRY

Date : 3 Sep 2014

Max Marks : 100 Time : 55 minutes

Section - I

Single Correct Answer Type(+3/0)

This section contains 12 multiple choice questions. Each question has 4 choices (a), (b), (c) and (d) for its answer, out of which ONLY ONE is correct.

  1. Which of the following is most reactive towards hydrogenation

(a) (b) (c) (d)

  1. O

C – O Product is –

O O

(a) C – O(b) C – O Cl

Cl

O O

(c) Cl C – O (d) C – O

Cl

  1. Which is most reactive towards chlorination

D D

(a) (b) (c) (d) all are equally reactive

D

  1. Which has higher dipole moment

(a) CH3Cl(b) CH2Cl(c) CHCl3(d) CH3F

  1. CH3

Product is –

OH

CH2Cl CH3 CH3 CH3

(a)(b)(c)(d) Cl

Cl

OH Cl OH OH

  1. Which of the following has highest boiling point among the isomers of C5H12O.

(a) CH3CH2 – CH2 – O – CH2 – CH3(b) CH3CH2CH2CH2CH2OH

(c) CH3CH OH CH2CH2CH3(d) (CH3)2 C OH CH2CH3

  1. CH3

CH3 CH3Total number of monosubstitution product of this

compound is/are –

CH3 CH3(a) 0(b) 1

CH3(c) 2(d) 3

  1. Which of the following does not give effervescence of CO2 with NaHCO3

(a) Formic acid(b) Carbolic acid(c) Salicylic acid(d) lactic acid

  1. Which is most acidic

OH OH OH

(a) NO2(b)(c) (d) all are equal

NO2

NO2

  1. Which occur as SN2

(a) CH3CH2OH (b) CH3CH2OH

CH3

(c) CH3C CH3 (d) all of these

OH

  1. To convert aniline into chlorobenzene the reagents required are

(a) NaNO2/HCl , CuCl2(b) NaNO2/HCl, Cu2Cl2

(c) NaNO2/HCl , Cl2/FeCl3(d) H3PO2 , Cl2/FeCl3

  1. An organic compound ‘A’ having molecular formula C8H8O give red orange precipitate with 2, 4-D.N.P. Compound ‘A’ does not give yellow precipitate with I2 and aqueous alkali. ‘A’ can be

O

(a) C – CH3(b) CH2 – CHO

(c) CH2 – CH2OH(d) CH – CH3

OH

Section - II

Single Correct Answer Type (+4/-1)

This section contains 6 multiple choice questions. Each question has 4 choices (a), (b), (c) and (d) for its answer, out of which ONLY ONE is correct.

  1. HBr

(A)(I) Reactively A > B for SN1

CH3 – CH = CH2 (II) Reactively A > B for SN2

(B)(III) Boiling point A > B

The correct statement(s) is/are

(a) I only (b) II only(c) I & III(d) II & III

  1. Br

CH3

Cl C Cl

OCH3 NO2

CH2Cl

Product is –

ONa Br

(a) CH3(b) CH3

Cl C Cl Cl C ONa

OCH3 NO2 OCH3 NO2

CH2ONa CH2ONa

ONa Br

(c) CH3(d) CH3

Cl C ONa NaO C ONa

OCH3 NO2 OCH3 NO2

CH2Cl CH2Cl

(A) (B)

(C) (D)

The correct statement is –

(a) B & D are position isomers (b) B & D are functional isomers

(c) B & D are Tautomers (d) B & D are same.

  1. In which case the product will not reduce Tollen’s reagent

(a) CH3 – CHCl2(b) CH3 – CH2OH

(c) CH3CH2OH (d) CH3 – CH = CH – CH3

  1. In which case(s) the product has zero dipole moment

SO3H N2+Cl– CH2OH

OH

(I) (II) (III) OH (IV)

SO3H N2+Cl– OH

(a) I & IV(b) II & III(c) IV(d) I, II, & III.

  1. An organic compound ‘A’ having molecular formula C4H10O neither reduce Tollen’s reagent nor decolorize bromine water but when treated with I2 and aqueous alkali it give yellow precipitate.

Total number of structure(s) possible for ‘A’ is/are (excluding sterioisomerism)

(a) 1(b) 2(c) 3(d) 4

Section - III

Matching Type (+4/-1)

This section contains 2 questions, each having two matching lists. Choice for the correct combinations of elements from List-I and List-II are given as option (a), (b), (c) and (d), out of which ONE is correct.

  1. List-I List-II

(P) Friedal Craft reaction(1) R – X + AgNO2 

(Q) Ambident nucleophilic(2) + R – X

CH3

(R) Product is ether(3) CH3 – C – Cl + C2H5ONa 

CH3

CH3

(S) Product is alkene(4) CH3 – C – ONa + C2H5Cl

CH3

Code :

P Q R S P Q R S

(a) 2 3 4 1 (b) 2 1 3 4

(c) 21 4 3 (d) 1 3 2 4

  1. List-I List-II

(P) D.D.T(1) Prepration of aldehyde

(Q) P.C.C (2) Ozone depletion

(R) Freon(3) Poisnous gas

(S) Phosgene(4) Insecticide

Code :

P Q R S P Q R S

(a) 1 4 2 3 (b) 4 1 3 2

(c) 24 1 3 (d) 4 1 2 3

Space for rough work

Section - IV

Comprehension type (+4/-1)

This section contains 3 multiple choice questions based on a paragraph. Each question has 4 choices (a), (b), (c) and (d) for its answer, out of which ONLY ONE is correct.

Friedal craft alkylation is a very important and most useful electrophillic aromatic

substitution reaction

R

+ R – X

Friedal craft reaction has two limitation (i) R – X R ,

this carbocation should be stable and it can rearrange to get stability (ii) If benzene ring is

deactivated or have amino group than Friedal craft reaction is not possible.

  1. To prepare 1–Phenyl propane which is better reaction

A  + CH3CH2CH2Cl

O

B  + CH3 – CH2 – C – Cl

C  + CH3 – CH = CH2

(a) A & B(b) A(c) B(d) all A, B & C give same product

  1. To convert benzene into metanitrotoluene, which method is most appropriate

A

B

(a) A(b) B(c) Any of ‘A’ & ‘B’ (d) None of these

  1. In the reaction , The electrophile is

(a) CH3(b) CH3(c) CH3(d) AlCl3

Space for rough work

Section - V

Integer type (+4/0)

This section contains 5 questions. The answer to each of the questions is a single digit integer, ranging from 0 to 9. The appropriate bubbles below the respective question numbers in the ORS have to be darkened. For example, if the correct answer to question numbers X, Y, Z and W (say) are 6, 0, 9 and 2, respectively, then the correct darkening of bubbles will look like the following :

  1. Among the following total number of compounds which are gas at room temperature (298 K)

CH3Cl, CH3Br, CH3CH2Cl, , CH3CH2CH3, CH3 – O – CH3,

CH3CH2OH, CH3OH, C2H5 –O – C2H5

  1. Among the following reactions, number of reaction(s) which will give CH3I as product –

(i) CH3 – OH ;(ii) CH3Cl ;(iii) CH3COOAg ;

(iv) CH3 – CH2 – O – CH3 ; (v) CH3 – O ;

CH3 CH3

(vi) CH3 – C – O – CH3 ; (vii) CH3 – CH – O – CH3

CH3

(viii) CH3OH

  1. H2NCH2 – CH – CH2 –CH2OH In I.U.P.A.C. name of this compound sum of locant is –

CH3

  1. Among the following total number of compound which have pKa less than pKa of H2O

CH  CH, CH2 = CH2, CH3OH, CH3CH2OH, CH3COOH, OH,

CH3NO2, , CH3NH2

  1. OIn the compound number of carbon atoms which are

sp3 hybridised

Me Me

Space for rough work

III-A/172 , Nehru Nagar Ghaziabad. Ph : 9811212090, 9868502091.

email : , website :

GT-2

TEST - 12th & 12th Passed

Topic : ORGANIC CHEMISTRY

Date : 03 SEP 2014

Max Marks : 100 Time : 55 minutes

Note : Write your name and roll no. above in box before filling the answers.

Section – I (Straight Objective Type +3/0) Section – II (Straight Objective Type +4/-1)

A B C D A B C D A B C D

1 7 13

2 8 14

3 9 15

410 16

511 17

61218

Section – III (Matching Type +4/-1)Section – IV (Comprehension Type +4/-1)

A B C D A B C D

19 21

20 22 23

Section – V (Integer Type +4/0)

0 1 2 3 4 5 6 7 8 9

24

25

26

27

28

BMC CLASSES Page No -1

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